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inessss [21]
3 years ago
11

Find the equation of a line that passes through the given points(-6,-5) and (6,-13)

Mathematics
2 answers:
NeTakaya3 years ago
5 0

Answer:

y+5=-3/4(x+6)

or in slope intercept

y= -3/4x-38/4

Step-by-step explanation:

To write the equation of a line we must have a slope and a point. To find the slope we use the slope formula and substitute (x,y) points in it as shown below:

m=\frac{y_2-y_1}{x_2-x_1}=\frac{-5--13}{-6-6}=\frac{-5+13}{-6+-6}=\frac{8}{-12}=\frac{-3}{4}

Now that we have the slope, plug in the slope and choose one point to plug into the point slope formula. Use the point-slope form to write the equation, then simplify and convert into the slope intercept form.

(y--5)=-3/4(x--6)

y+5=-3/4(x+6)

y+5=-3/4x-18/4

y=-3/4x-18/4-20/4

y= -3/4x-38/4



Evgen [1.6K]3 years ago
4 0

Hello there,

Find the equation of a line that passes through the given points

(-6,-5) and (6,-13)

Answer: -3/4x-38/4

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