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babymother [125]
3 years ago
14

Find the inverse function

Mathematics
1 answer:
Troyanec [42]3 years ago
4 0

The inverse of the function is f(x) = x^{3} + 8

In order to find the inverse of any function, start by switching the f(x) and x. Then solve for the new f(x). The result will be the inverse function. The work is below for you.

f(x) = \sqrt[3]{x - 8} ----> Switch f(x) and x

x = \sqrt[3]{f(x) - 8} ----> Cube both sides

x^{3} = f(x) - 8 ----> Add 8 to both sides

f(x) = x^{3} + 8

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Solve the following equation on the interval [0, 2π). tan^2x sin x = tan^2x
Alenkasestr [34]
<h3>Given</h3>

tan(x)²·sin(x) = tan(x)²

<h3>Find</h3>

x on the interval [0, 2π)

<h3>Solution</h3>

Subtract the right side and factor. Then make use of the zero-product rule.

... tan(x)²·sin(x) -tan(x)² = 0

... tan(x)²·(sin(x) -1) = 0

This is an indeterminate form at x = π/2 and undefined at x = 3π/2. We can resolve the indeterminate form by using an identity for tan(x)²:

... tan(x)² = sin(x)²/cos(x)² = sin(x)²/(1 -sin(x)²)

Then our equation becomes

... sin(x)²·(sin(x) -1)/((1 -sin(x))(1 +sin(x))) = 0

... -sin(x)²/(1 +sin(x)) = 0

Now, we know the only solutions are found where sin(x) = 0, at ...

... x ∈ {0, π}

8 0
3 years ago
How much would $100 invested at 8% intrest compounded annually be worth after 15 years? round your answer to the nearest cent. d
frosja888 [35]
Our P = 100, r = .08, n = 1 (annually means once a year), and t = 15.  Filling in accordingly, we have A(t)=100(1+ \frac{.08}{1})^{(1)(15)}.  Simplifying a bit gives us  A(t)=100(1+.08)^{15}  and  A(t)=100(1.08)^{15}.  Raising that number inside the parenthesis to the 15th power gives us  A(t)=100(3.172169114).  Multiplying to finish means that A(t) = $317.22
3 0
4 years ago
1. Among 806 people asked which is there favorite seat on a plane, 492 chose the window seat, 8 chose the middle seat, and 306 c
prisoha [69]

Answer:

See explanation

Step-by-step explanation:

Among 806 people asked which is there favorite seat on a plane, 492 chose the window seat, 8 chose the middle seat, and 306 chose the aisle seat, then

P(\text{Window seat})=\dfrac{492}{806}=\dfrac{246}{403}\\ \\P(\text{Middle seat})=\dfrac{8}{806}=\dfrac{4}{403}\\ \\P(\text{Aisle seat})=\dfrac{306}{806}=\dfrac{153}{403}

a) One randomly selected person preferes aisle seat with probability

\dfrac{153}{403}

b) Two randomly selected people both prefer aisle seat (with replacement) is

\dfrac{306}{806}\cdot \dfrac{306}{806}=\dfrac{153}{403}\cdot \dfrac{153}{403}=\dfrac{23,409}{162,409}

c) Two randomly selected people both prefer aisle seat (without replacement) is

\dfrac{306}{806}\cdot \dfrac{305}{805}=\dfrac{153}{403}\cdot \dfrac{61}{161}=\dfrac{9,333}{64,883}

8 0
3 years ago
PLZ HELP ASAP!!!<br> I really don’t understand these problems hope you guys can help!
Reil [10]

Answer:

#6 is 1001

#8 is x=1312

Step-by-step explanation:

6. 11*13*7= 1001

8. 32*41=x

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5 0
3 years ago
Suppose an auto racer won a 400 mile race with a time of ​1:41​:58. at one point the racer was 40 miles closer to the finish tha
enot [183]
400/2 = 200
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200 - 20 = 180
Answer: He had gone 220 miles.

He was 180 miles from the finish and 220 from the start, so he was 40 miles closer to the finish than to the start.
7 0
3 years ago
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