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2 years ago

PL HELP ASAP

Mathematics

2 answers:

kotykmax [81]2 years ago

6 0

(x+10)2
+
(2x-5)2
-
(x+1)4

klasskru [66]2 years ago

4 0

Answer:

x²+23x+49

Step-by-step explanation:

The area of the large rectangle can be found by multiplying the dimensions, x+10 and 2x+5:

(x+10)(2x+5)

x(2x)+5(x)+10(2x)+10(5)

2x²+5x+20x+50

2x²+25x+50

Next find the area of the smaller rectangle. Do this by multiplying x+1 by x+1:

(x+1)(x+1)

x(x)+1(x)+1(x)+1(1)

x²+1x+1x+1

x²+2x+1

Now subtract the larger area and the smaller area:

(2x²+25x+50)-(x²+2x+1)

To do this, combine like terms:

2x²-x²+25x-2x+50-1

x²+23x+49

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Jace is a songwriter who collects royalties in his songs whenever they are played in a commercial or a movie. Jace will earn $50

VashaNatasha [74]

Jace's song were played on 8 commercials and 2 movies

<h3>Further explanation</h3>

Simultaneous Linear Equations could be solved by using several methods such as :

<em>Elimination Method</em>
<em>Substitution Method</em>
<em>Graph Method</em>

If we have two linear equations with 2 variables x and y , then we need to find the value of x and y that satisfying the two equations simultaneously.

Let us tackle the problem!

<em>Number of Commercials = C</em>

<em>Number of Movies = M</em>

$\texttt{ }$

<em>Jaces songs were played on 6 more commercials than movies.</em>

$\boxed{C = 6 + M}$ → <em>Equation 1</em>

$\texttt{ }$

<em>Jace will earn $50 every time one of his songs is played in a commercial and he will earn $140 every time one of his songs is played in a movie.</em>

<em>His total earnings in the royalties from all commercials and movies was $680.</em>

$\boxed{50C + 140M = 680}$ → <em>Equation 2</em>

$\texttt{ }$

<em>Equation 1 ↔ Equation 2 :</em>

$50C + 140M = 680$

$50 ( 6 + M ) + 140M = 680$

$300 + 50M + 140M = 680$

$190M = 680 - 300$

$190M = 380$

$M = 380 \div 190$

$M = 2$

$\texttt{ }$

$C = 6 + M$

$C = 6 + 2$

$C = 8$

$\texttt{ }$

<h2>Conclusion:</h2>

The number of commercials and the number of movies in which Jaces songs where played is respectively 8 and 2

$\texttt{ }$

<h3>Learn more</h3>

Perimeter of Rectangle : brainly.com/question/12826246
Elimination Method : brainly.com/question/11233927
Sum of The Ages : brainly.com/question/11240586

<h3>Answer details</h3>

Grade: High School

Subject: Mathematics

Chapter: Simultaneous Linear Equations

Keywords: Simultaneous , Elimination , Substitution , Method , Linear , Equations

5 0

3 years ago

Psychologist Michael Cunningham conducted a survey of university women to see whether, upon graduation, they would prefer to mar

bagirrra123 [75]

Answer:

A.The probability that exactly six of Nate's dates are women who prefer surgeons is 0.183.

B. The probability that at least 10 of Nate's dates are women who prefer surgeons is 0.0713.

C. The expected value of X is 6.75, and the standard deviation of X is 2.17.

Step-by-step explanation:

The appropiate distribution to us in this model is the binomial distribution, as there is a sample size of n=25 "trials" with probability p=0.25 of success.

With these parameters, the probability that exactly k dates are women who prefer surgeons can be calculated as:

$P(x=k) = \dbinom{n}{k} p^{k}(1-p)^{n-k}\\\\\\P(x=k) = \dbinom{25}{k} 0.25^{k} 0.75^{25-k}\\\\\\$

A. P(x=6)

$P(x=6) = \dbinom{25}{6} p^{6}(1-p)^{19}=177100*0.00024*0.00423=0.183\\\\\\$

B. P(x≥10)

$P(x\geq10)=1-P(x$

$P(x=0) = \dbinom{25}{0} p^{0}(1-p)^{25}=1*1*0.0008=0.0008\\\\\\P(x=1) = \dbinom{25}{1} p^{1}(1-p)^{24}=25*0.25*0.001=0.0063\\\\\\P(x=2) = \dbinom{25}{2} p^{2}(1-p)^{23}=300*0.0625*0.0013=0.0251\\\\\\P(x=3) = \dbinom{25}{3} p^{3}(1-p)^{22}=2300*0.0156*0.0018=0.0641\\\\\\P(x=4) = \dbinom{25}{4} p^{4}(1-p)^{21}=12650*0.0039*0.0024=0.1175\\\\\\P(x=5) = \dbinom{25}{5} p^{5}(1-p)^{20}=53130*0.001*0.0032=0.1645\\\\\\P(x=6) = \dbinom{25}{6} p^{6}(1-p)^{19}=177100*0.0002*0.0042=0.1828\\\\\\$

$P(x=7) = \dbinom{25}{7} p^{7}(1-p)^{18}=480700*0.000061*0.005638=0.1654\\\\\\P(x=8) = \dbinom{25}{8} p^{8}(1-p)^{17}=1081575*0.000015*0.007517=0.1241\\\\\\P(x=9) = \dbinom{25}{9} p^{9}(1-p)^{16}=2042975*0.000004*0.010023=0.0781\\\\\\$