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3 years ago

PL HELP ASAP

Mathematics

2 answers:

kotykmax [81]3 years ago

6 0

(x+10)2
+
(2x-5)2
-
(x+1)4

klasskru [66]3 years ago

4 0

Answer:

x²+23x+49

Step-by-step explanation:

The area of the large rectangle can be found by multiplying the dimensions, x+10 and 2x+5:

(x+10)(2x+5)

x(2x)+5(x)+10(2x)+10(5)

2x²+5x+20x+50

2x²+25x+50

Next find the area of the smaller rectangle. Do this by multiplying x+1 by x+1:

(x+1)(x+1)

x(x)+1(x)+1(x)+1(1)

x²+1x+1x+1

x²+2x+1

Now subtract the larger area and the smaller area:

(2x²+25x+50)-(x²+2x+1)

To do this, combine like terms:

2x²-x²+25x-2x+50-1

x²+23x+49

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where
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First we need to convert our interest rate of 4% to decimal form by dividing it by 100%:
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We also know from our question that $P=224500$ and $t=30$ , so lets replace those values into our formula to find the monthly payment:
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7 0

3 years ago

10 points if you can answer what percent of 20 <br> Is 0.6

UNO [17]

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3 years ago

The Resource Conservation and Recovery Act mandates the tracking and disposal of hazardous waste produced at U.S. facilities. Pr

aniked [119]

Answer:

(a) $E(X) = 0.383$

The expected number in the sample that treats hazardous waste on-site is 0.383.

(b) $P(x = 4) = 0.000169$

There is a 0.000169 probability that 4 of the 10 selected facilities treat hazardous waste on-site.

Step-by-step explanation:

Professional Geographer (Feb. 2000) reported the hazardous waste generation and disposal characteristics of 209 facilities.

N = 209

Only eight of these facilities treated hazardous waste on-site.

r = 8

a. In a random sample of 10 of the 209 facilities, what is the expected number in the sample that treats hazardous waste on-site?

n = 10

The expected number in the sample that treats hazardous waste on-site is given by

$E(X) = \frac{n \times r}{N}$

$E(X) = \frac{10 \times 8}{209}$

$E(X) = \frac{80}{209}$

$E(X) = 0.383$

Therefore, the expected number in the sample that treats hazardous waste on-site is 0.383.

b. Find the probability that 4 of the 10 selected facilities treat hazardous waste on-site

The probability is given by

$P(x = 4) = \frac{\binom{r}{x} \binom{N - r}{n - x}}{\binom{N}{n}}$

For the given case, we have

N = 209

n = 10

r = 8

x = 4

$P(x = 4) = \frac{\binom{8}{4} \binom{209 - 8}{10 - 4}}{\binom{209}{10}}$

$P(x = 4) = \frac{\binom{8}{4} \binom{201}{6}}{\binom{209}{10}}$

$$ P(x = 4) = \frac{70 \times 84944276340}{35216131179263320}$

$P(x = 4) = 0.000169$

Therefore, there is a 0.000169 probability that 4 of the 10 selected facilities treat hazardous waste on-site.

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3 years ago

Mr. Johns gave a test last week and Ginny missed one question. She answered that 14.5 people would ride on each bus rather than

Mars2501 [29]

Mr. Johns handle this situation to Agree to meet, listen to their concerns, and then explaining that one component of math is understanding reasonable answers.

Mr. Johns gave a test last week and Ginny missed one question. She answered that 14.5 people would ride on each bus rather than 15. Her parents would like a conference because she did the math problem correctly and should receive credit even though her answer was not reasonable.

Mr. Johns handle this situation to Agree to meet, listen to their concerns, and then explain that one component of math is understanding reasonable answers.

Learn more about the reasoning here brainly.com/question/25175983

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2 years ago

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balu736 [363]

Answer:

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Step-by-step explanation:

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