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Dovator [93]
3 years ago
5

-2 3/4 ÷ -1/7= help​

Mathematics
1 answer:
Hitman42 [59]3 years ago
3 0

The answer is 19\frac{1}{4}

First you must set up the equation

-2\frac{3}{4}÷-\frac{1}{7}

First, you must make the mixed number a improper fraction

-\frac{11}{4}÷-\frac{1}{7}

Then you must divide

\frac{77}{4}

Finally, simplify

19\frac{1}{4}

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How do I solve for y?
Allisa [31]

First we know that,

3x+15=5x-65 because of vertical angle thr.

y=y because of reflex property

there are 360 degrees in a circle so..

3x+15+5x-65+2y=360

3x+15=5x-65

x=40

so each 2 of the angles are...(40*3+15)=135

Then your new equation is

135+135+2y=360

2y=90

<u>y=45</u>

Hope this helps :)


5 0
3 years ago
What is the angle measure of 2x+1°
Ray Of Light [21]

Answer:

25 degrees

Step-by-step explanation:

Haha, awesome! Just did a problem like this!

All angles add up to 180, so set it up like this:

2x + 1 + 5x + 5 + 90 = 18

Combine like terms.

7x + 96 = 180

7x = 84

x = 12

Plug x back into 2x + 1

2(12) + 1

24 + 1

= 25 degrees

While we're at it...

5(12) + 5

60 + 5

= 65 degrees (for the other angle)

25 + 65 + 90 = 180

Math checks out & we're good to go!

Hope this helped. :) <3

5 0
2 years ago
25x² - 4 <br>I'm trying to help a friend n that's all they gave me ahh
torisob [31]
This is a difference of squares problem. You just have to make sure every term is a perfect square and that there is subtraction in the problem.

7 0
3 years ago
Evaluate x + 8 when x = 7<br><br> a. 15<br><br> b. 1<br><br> c. -1<br><br> d. 56
Tems11 [23]

Answer:

a) 15

Step-by-step explanation:

x+8

substitute x value in

7+8

=15

8 0
3 years ago
Read 2 more answers
Solve 15 ≥ -3x or 2/3 x ≥ -2.
hjlf
Solve each of the equations independently, then determine if the are continuous or discontinuous. 
15≥-3x [start here]
-5≤x    [divide both sides by (-3). *Dividing by a negative number means the direction of the sign changes!]
x≥-5  [just turned around for analysis]

Next equation:
2/3x≥-2    [start here]
x≥-2(3/2)  [multiply both sides of the equation by the reciprocal, 3/2)
x≥-3

So, (according to the first equation) all values of x must be greater than, or equal to -5.

(According to the second equation) all values of x must be greater than, or equal to -3. 
So, when graphed on a number line, both equations graph in the same direction, so they are continuous.

4 0
3 years ago
Read 2 more answers
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