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2 years ago

9

Evaluate.

ass="latex-formula">

2 answers:

ch4aika [34]2 years ago

7 0

4^0 is 1 because any number to the zero power is one so 1*5=5

disa [49]2 years ago

7 0

Hey there!

When you have this equation, and you have $4^{0}$ it turns to $4^{1}$

So now do 4 x 1 = 4

Now do 5 x 4 = 20

Your final answer is 20.

Hope this helps! Let me know if you need help with anything else. :)

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Ill give you 28 points if you answer this!!

elena-14-01-66 [18.8K]

Answer:

D

Step-by-step explanation:

because youe last number is 90

6 0

2 years ago

3.5x - 11 = 20.5 what does x equal?

stepan [7]

Answer:

x=9

Step-by-step explanation:

3.5x - 11 = 20.5

Add 11 to each side

3.5x - 11+11 = 20.5+11

3.5x = 31.5

Divide each side by 3.5x

3.5x/3.5 = 31.5/3.5

x =9

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2 years ago

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How can you remember slope? in a creative way

lianna [129]

Answer:

Step-by-step explanation:

dont have a creative way but i just remember rise over run or $\frac{rise}{run}$

hope this helps <3

7 0

2 years ago

Read 2 more answers

Describe the transformation of f(x) to g(x)

gulaghasi [49]

Answer:

D. f(x) is shifted up 1 unit to g(x).

Step-by-step explanation:

Just let's look at the y-intercept of each function.

f(0) = 0

g(0) = 1

Also remember that a vertical shift of N units is written as:

g(x) = f(x) + N

where if N is positive, the shift is upwards, and if N is negative, the shift is downwards.

then we can write, for the particular value x = 0

g(0) = f(0) + N

replacing the values

1 = 0 + N

1 = N

Then N is positive, so we have a shift up of one unit.

The correct option is:

D. f(x) is shifted up 1 unit to g(x).

6 0

2 years ago

Two athletic teams play a series of games; the first team to win 4 games is declared the overall winner. Suppose that one of the

kodGreya [7K]

Answer:

p=0.7103 (4-game series)
p=0.6480 (2-game series)

Step-by-step explanation:

Let X be the random variable equal the the first 4 straight wins. An overall win for the stronger team implies a negative binomial function with the parameters n=4, p=0.6:

$P(X=4)={{i-1}\choose {4-1}}0.6^40.4^{i-4},\ i=4,5,6,7$

#We find probabilities for the different values of i:

$P(X=4)={3\choose 3}0.6^4=0.1296\\\\P(X=5)={4\choose 3}0.6^40.4^1=0.2074\\\\P(X=6)={5\choose 3}0.6^40.4^2=0.2074\\\\P(X=4)={6\choose 3}0.6^40.4^3=0.1659$

Hence, probability of the stronger team winning overall is:

$=P(X=4)+P(X=5)+P(X=6)+P(X=7)\\\\=0.7103$

#Define Y as the random variable for winning 2/3 games.:

$P(Y=2)={1\choose 1}0.6^2=0.3600\\\\P(Y=3)={2\choose3}0.6^20.4=0.2880\\\\P(win)=0.2880+0.3600=0.6480$

Hence, probability of the stronger team winning in 2 out 3 game series is 0.6480

The stronger team has a higher chance of winning in a 4-game series(0.7103>0.6480)

8 0

2 years ago