Answer:
There were 6 benches in park 1 and 18 benches in park 2.
Step-by-step explanation:
Let x be the no of benches in Park 1 and y in park 2.
Given that there are 12 more benches in park 2 than 1
Writing this in equation form, we have y = x+12 ... i
Next is if 2 benches were transferred from park 2 to park 1, then we have
x+2 in park 1 and y-2 in park 2.
Given that y-2 = twice that of x+2
Or y-2 = 2x+4 ... ii
Rewrite by adding 2 to both sides of equation ii.
y = 2x+6 ... iii
i-iii gives 0 = -x+6
Or x =6
Substitute in i, to have y = 6+12 = 18
Verify:
Original benches 6 and 18.
18 = 6+12 hence I condition is satisfied
18-2 = 2(6+2)
II is also satisfied.

First, take about the

and


You can cancel out the two 3's on the bottom using two of the threes from the numerator

Simplify the fraction
3 x 3 Multiply
9
Answer:
Mean = 35
Variance = 291.7
Step-by-step explanation:
Data provided in the question:
X : 1, 2, 3, 4, 5, 6
All the data are independent
Thus,
The mean for this case will be given as:
Mean, E[X] = 
or
E[X] = 
or
E[X] = 3.5
For 10 days, Mean = 3.5 × 10 = 35
And,
variance = E[X²] - ( E[X] )²
Now, for this case of independent value,
E[X²] = 
or
E[X²] = 
or
E[X²] = 
or
E[X²] = 15.167
Therefore,
variance = E[X²] - ( E[X] )²
or
variance = 15.167 - 3.5²
or
Variance = 2.917
For 10 days = Variance × Days²
= 2.917 × 10²
= 291.7
.01 is the answer to that or one one hundredth