Ab=81, a=81/b
s=a+b using a from above in this we get:
s(b)=81/b +b
s(b)=(81+b^2)/b
ds/db=(2b*b-81-b^2)/b^2
ds/db=(2b^2-81-b^2)/b^2
ds/db=(b^2-81)/b^2
d2s/db2=(2b^3-2b^3+81)/b^4
d2s/db2=81/b^4 since b is positive we know that the acceleration is positive so that when ds/db=0 it is a minimum for s(b)
ds/db=0 only when b^2-81=0, b^2=81, b=9
The two positive numbers are 9 and 9.
A. (Area of triangle UVW)/(Area of triangle RST)=3^2=9
B. Substitute Area of triangle RST=9 into the equation above.
(Area of triangle UVW)/9=9
Area of triangle UVW =9x9=81 cm^2
I think the answer is C hope this would help you
First, you would need to create an equation for this problem. Let x represent the number of sales made.
$100 + $3x = $160
Next, you would need to isolate the x.
Subtract $100 from both sides.
$3x = $60
Now, all you would need to do is divide both sides by $3.
x = 20
You would need to make at least 20 sales.
I hope this helps!
