Answer:
If this is a proof then here is the answer.
Angle ABD is Congruent to Angle CBD = Given
Angle BDA is Congruent to Angle BDC = Given
Angle ABD is Congruent to Angle CBD = Definition of Angle Bisector
Line Segment BD is Congruent to Line Segment BD = Reflexive Property
Line Segment AB is Congruent to Linge Segment CB = Angle-Side-Angle or ASA
Step-by-step explanation:
Lucky for you, I just learned this also ;)
Since you are given your first two directions, put them down as GIVEN in the proof.
Next, Since ABD and CBD are congruent angles, you can assume that it is an angle bisector since angle bisectors always bisect equally.
Then, (This one is obvious), since Line Segment BD shares a side with itself, it is equal by the Reflexive Property (EX: AB is congruent to AB).
Finally, Since there is two angles with a congruent side in the middle, you can confirm that it is equal by Angle-Side-Angle.
Hope this helped!
ANSWER: y=7 is the equation Of the line that passes to through the point (-2,7) and Has a slope of zero.
![\sf{14(\sqrt[3]{x}) }](https://tex.z-dn.net/?f=%5Csf%7B14%28%5Csqrt%5B3%5D%7Bx%7D%29%20%7D)
Step-by-step explanation:
![5(\sqrt[3]{x})+9(\sqrt[3]{x})\\\\(5+9)(\sqrt[3]{x})\\\\14(\sqrt[3]{x})](https://tex.z-dn.net/?f=5%28%5Csqrt%5B3%5D%7Bx%7D%29%2B9%28%5Csqrt%5B3%5D%7Bx%7D%29%5C%5C%5C%5C%285%2B9%29%28%5Csqrt%5B3%5D%7Bx%7D%29%5C%5C%5C%5C14%28%5Csqrt%5B3%5D%7Bx%7D%29)
First You Have To Plot It At -3 On the Graph And Go Up 2 And Over To The Right 3
