Answer:
Proved
Step-by-step explanation:
To prove that every point in the open interval (0,1) is an interior point of S
This we can prove by contradiction method.
Let, if possible c be a point in the interval which is not an interior point.
Then c has a neighbourhood which contains atleast one point not in (0,1)
Let d be the point which is in neighbourhood of c but not in S(0,1)
Then the points between c and d would be either in (0,1) or not in (0,1)
If out of all points say d1,d2..... we find that dn is a point which is in (0,1) and dn+1 is not in (0,1) however large n is.
Then we find that dn is a boundary point of S
But since S is an open interval there is no boundary point hence we get a contradiction. Our assumption was wrong.
Every point of S=(0, 1) is an interior point of S.
A term is a number or variable in a math sentence (such as an expression or equation).
Example:
a + 2b + c + 5
5 is a constant; a,b, c are all variables.
Answer:
it should be 2/12 and 9/11
Step-by-step explanation:
Answer:
(5x-4y)=19
5×19-4×19
95-76
19
Step-by-step explanation:
x+2y=8
x=8-2
x=6
<span>2<span>x2</span>+xy+2<span>y2</span>=5</span>Implicit differentiation yields<span>4x+y+x<span>y′</span>+4y <span>y′</span>=0</span>Solve for <span>y′</span><span>.
answer is- y = 4x+ y /5x</span>
