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inna [77]
3 years ago
13

The compound zinc fluoride is a strong electrolyte. write the transformation that occurs when solid zinc fluoride dissolves in w

ater.
Chemistry
1 answer:
Svetach [21]3 years ago
4 0
Strong electrolytes by definition are those compounds that completely dissociates into their component ions when dissolved in water. The chemical formula for the zinc fluoride is,
               ZnF2
This means that each formula unit is composed of one atom of zinc and 2 atoms of fluoride. The ions comprising the unit are Zn²⁺ and F⁻. The dissociation is as shown below,
              ZnF₂ -->  Zn²⁺  + 2F⁻
When dissolved in water it is expected that the compound dissociates into three different ions, one Zn²⁺ and two F⁻. 
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Ethanol (CH3CH2OH), the intoxicant in alcoholic beverages, is also used to make other organic compounds. In concentrated sulfuri
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Answer:

a) 88.48%

b) 0.05625 mol

Explanation:

2CH₃CH₂OH(l) → CH₃CH₂OCH₂CH₃(l) + H₂O(g)         Reaction 1

CH₃CH₂OH(l) → CH₂═CH₂(g) + H₂O(g)                        Reaction 2

a) CH₃CH₂OH = 46.0684 g/mol

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1 mol CH₃CH₂OH ______  46.0684 g

x                            ______   50.0 g

x = 1.085 mol  CH₃CH₂OH

1 mol  CH₃CH₂OCH₂CH₃ ______  74.12 g g

y                           ______   35.9 g

y = 0.48 mol   CH₃CH₂OCH₂CH₃

100% yield _____ 0.5425 mol CH₃CH₂OCH₂CH₃

w                _____  0.48 mol CH₃CH₂OCH₂CH₃

w = 88.48%

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