The –OH+ group is most acidic proton in ln-OH as shown in figure (a). The proton is circled in the figure.
The stabilisation of the conjugate base produced is stabilises due to resonance factor. The possible resonance structures are shown in figure (b).
The acidity of a protonated molecule depends upon the stabilisation of the conjugate base produced upon deprotonation. The conjugate base of ln-OH is shown in figure (a).
The possible resonance structures are shown in figure (b). As the number of resonance structures of the conjugate base increases the stabilisation increases. Here the unstable quinoid (unstable) form get benzenoid (highly stable) form due to the resonance which make the conjugate base highly stabilise.
Thus the most acidic proton is assigned in ln-OH and the stability of the conjugate base is explained.
SI units or International System of Units is defined as basic set of measurement of seven units. The physical quantities and base units are as follows:
Length is measured in meter (m), mass in kilogram (kg), time in second (s), electric current in ampere (A), temperature in Kelvin (K), luminous intensity in candela (cd) and amount of substance in mole (mol).
Therefore, SI units of physical quantities is known as base units and other units are known as derived units because they can derived from the SI units.
Thus, the correct match will be:
From the rest of the units, degree Fahrenheit is derived unit for temperature, gram is derived unit for mass, nanosecond is derived unit for time and candela is SI unit for luminous intensity.
Answer:
Particle density is the volumetric mass of the solid soil. It differs from bulk density because the volume used does not include pore spaces. Particle density represents the average density of all the minerals composing the soil.
Hope that helps
A first order reaction, with a half-life of 125 s, has 1/16 of the original amount left after 500 seconds.
<h3>What is a first order reaction?</h3>
It is a chemical reaction in which the rate of reaction is directly proportional to the concentration of the reacting substance.
First, we will calculate the rate constant using the following expression.
ln ([A]/[A]₀) = - k × t
ln (1/16[A]₀/[A]₀) = - k × 500 s
k = 5.55 × 10⁻³ s⁻¹
where,
- [A] is the final concentration of the reactant.
- [A]₀ is the initial concentration of the reactant.
- k is the rate constant.
- t is the elapsed time.
Next, we can calculate the half-life (th) using the following expression.
th = ln 2 / k = ln 2 / (5.55 × 10⁻³ s⁻¹) = 125 s
A first order reaction, with a half-life of 125 s, has 1/16 of the original amount left after 500 seconds.
Learn more about first order reactions here: brainly.com/question/518682
