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Tcecarenko [31]
3 years ago
5

The climate in the temperate deciduous forest biome has four changing seasons with rain.

Chemistry
1 answer:
neonofarm [45]3 years ago
5 0
The answer is false.
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5. Which of the following statements is incorrect?
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c- dry cells can not be recharged

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2 years ago
5. Which of the following can be classified as a mixture ?
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5. B air is a mixture of many elements, but is not a chemically fused.


6. B Beef stew, composition varies throughout.


7. A. They can be chemically separated into their component elements, but they are all homogenous, and as such, have constant composition, which differs from the components properties, as the components must undergo a chemical change to become compounds.

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3 years ago
Which diagram shows how the particles of the solid substance will look after it has absorbed enough heat to melt partially ??
cricket20 [7]
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4 0
3 years ago
Please help on 44. /45./ 46./47,
Aleonysh [2.5K]
The only one that I can do without google is 47. Sorry that I can't answer the others. The answer to 47 is this: you know that the western side of the hill has the steepest slope because the ovals showing altitude are way closer together. The closer the circles/ovals are, the steeper the slope is.

Sorry if this doesn't help much, but I answered what I could without cheating.

Foxeslair
4 0
3 years ago
At 25°C and constant pressure, carbon monoxide gas combines with oxygen gas to give carbon dioxide gas with the evolution of 10.
stealth61 [152]

Answer : The value of \Delta H for the reaction is, -565.6 kJ

Explanation :

First we have to calculate the molar mass of CO.

Molar mass CO = Atomic mass of C + Atomic mass of O  = 12 + 16 = 28 g/mole

Now we have to calculate the moles of CO.

\text{Moles of }CO=\frac{\text{Mass of }CO}{\text{Molar mass of }CO}=\frac{1g}{28g/mole}=\frac{1}{28}mole

Now we have to calculate the value of \Delta H for the reaction.

The balanced equation will be,

2CO(g)+O_2(g)\rightarrow 2CO_2(g)

From the balanced chemical reaction we conclude that,

As, \frac{1}{28}mole of CO release heat = 10.1 kJ

So, 2 mole of CO release heat = 2\times 28\times 10.1=565.6kJ

Therefore, the value of \Delta H for the reaction is, -565.6 kJ (The negative sign indicates the amount of energy is released)

4 0
3 years ago
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