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3 years ago

- 3/5 or - 0.6 which is greater

Mathematics

2 answers:

Dimas [21]3 years ago

7 0

They are both the same as -0.6 is -3/5 converted to fractions

Phoenix [80]3 years ago

5 0

They are equal because -3/5 is -6.

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Based on aâ poll, among adults who regret gettingâ tattoos, 18â% say that they were too young when they got their tattoos. Assum

Sergeeva-Olga [200]

Answer:

a) 20.44% probability that none of the selected adults say that they were too young to get tattoos.

b) 35.90% probability that exactly one of the selected adults says that he or she was too young to get tattoos.

c) 56.34% probability that the number of selected adults saying they were too young is 0 or 1.

d) No

Step-by-step explanation:

For each adult, there are only two possible outcomes. Either they say they were too young when they got their tattoos, or they don't say that. Each adult is independent of each other. So we use the binomial probability distribution to solve this question.

Binomial probability distribution

The binomial probability is the probability of exactly x successes on n repeated trials, and X can only have two outcomes.

$P(X = x) = C_{n,x}.p^{x}.(1-p)^{n-x}$

In which $C_{n,x}$ is the number of different combinations of x objects from a set of n elements, given by the following formula.

$C_{n,x} = \frac{n!}{x!(n-x)!}$

And p is the probability of X happening.

18% say that they were too young when they got their tattoos.

This means that $p = 0.18$

Eight adults who regret getting tattoos are randomly selected

This means that $n = 8$

a. Find the probability that none of the selected adults say that they were too young to get tattoos.

This is P(X = 0).

$P(X = x) = C_{n,x}.p^{x}.(1-p)^{n-x}$

$P(X = 0) = C_{8,0}.(0.18)^{0}.(0.82)^{8} = 0.2044$

20.44% probability that none of the selected adults say that they were too young to get tattoos.

b. Find the probability that exactly one of the selected adults says that he or she was too young to get tattoos.

This is P(X = 1).

$P(X = x) = C_{n,x}.p^{x}.(1-p)^{n-x}$

$P(X = 1) = C_{8,1}.(0.18)^{1}.(0.82)^{7} = 0.3590$

35.90% probability that exactly one of the selected adults says that he or she was too young to get tattoos.

c. Find the probability that the number of selected adults saying they were too young is 0 or 1.

Either a. or b.

20.44 + 35.90 = 56.34

56.34% probability that the number of selected adults saying they were too young is 0 or 1.

d. It we randomly select 9 adults. Is 1 a significantly low number who day that they were too young to get tattoos?

Now $n = 9$

It is significantly low if it is more than 2.5 standard deviations below the mean.

The mean is $E(X) = np = 9*0.18 = 1.62$

The standard deviation is $\sqrt{V(X)} = \sqrt{n*p*(1-p)} = \sqrt{9*0.18*0.82} = 1.15$

1 > (1.62 - 2.5*1.15)

So the answer is no.

5 0

2 years ago

Stan is on a bike ride. His GPS indicates that he has traveled exactly 18 miles and he is 32% complete with his total ride.

Semenov [28]

100 / 32 = 3.125
3.125 * 18 = 56.25.

Stan's bike ride is 56.25 miles long.

8 0

3 years ago

Solve for x. topic: pythagorean theorem

Eduardwww [97]

Answer:

X = 10.7

Step-by-step explanation:

25^2 - 16^2 = 369 which squared is approximately 19.2. We need X which is the smaller side so we minus 22^2 from 19.2^2 which is 115.36 which is squared to 10.7

4 0

3 years ago

Assigned Media

VashaNatasha [74]

Answer:

Jon Applebe withdrew 37.15% of the amount he initially deposited.

Step-by-step explanation:

Given that Jon Applebee deposited $ 619 in his savings account, and I have later withdrew $ 230, to determine the integer that represents the amount Jon Applebee deposited the following calculation must be performed:

619 = 100

230 = X

230 x 100/619 = X

23,000 / 619 = X

37.15 = X

Therefore, Jon Applebe withdrew 37.15% of the amount he initially deposited.

6 0

2 years ago

Write a variable expression to represent the phrase. The difference of a number and 1

umka2103 [35]

Answer:

$x-1$

Step-by-step explanation:

Hi there!

Let $x$ represent "the number".

The difference of a number and 1

⇒ $x-1$

I hope this helps!

4 0

2 years ago