Ask question

Ask question

All categories

3 years ago

10

four time the first of three consecutive integers is six more than the product of two and the third integer. find the integers.

1 answer:

maw [93]3 years ago

3 0

<span>
Assign variables :
Let x = first consecutive even
Let x + 2 = second consecutive even
Let x + 4 = third consecutive even
4x = 6 + 2(x+4)
4x = 6 + 2x + 8
4x = 2x + 14
4x - 2x = 14
so your answer is 7,9and 11</span>

You might be interested in

Just one bacterium, dividing every 20 minutes could produce nearly 5 billion bacteria in one day. Could this be correct or a mis

faust18 [17]

The equation (1•2)^72 (72 20 minute periods in a day) would produce way more than 5 billion a day

5 0

2 years ago

Please help please please

diamong [38]

Answer:

d

Step-by-step explanation:

there is only 4 of her ponies that are over 96 centimeters but it is not 40 percent but 27 percent because she has 14 ponies not 10 ponies

8 0

2 years ago

The vertices of ∆ABC are A(-2, 2), B(6, 2), and C(0, 8). The perimeter of ∆ABC is units is? What is the area?

11111nata11111 [884]

we have

$A(-2, 2),B(6, 2),C(0, 8)$

see the attached figure to better understand the problem

we know that

The perimeter of the triangle is equal to

$P=AB+BC+AC$

and

the area of the triangle is equal to

$A=\frac{1}{2}*base *heigth$

in this problem

$base=AB\\heigth=DC$

we know that

The distance between two points is equal to

$d=\sqrt{(y2-y1)^{2}+(x2-x1)^{2}}$

Step $1$

<u>Find the distance AB</u>

$A(-2, 2),B(6, 2)$

Substitute the values in the formula

$d=\sqrt{(2-2)^{2}+(6+2)^{2}}$

$d=\sqrt{(0)^{2}+(8)^{2}}$

$dAB=8\ units$

Step $2$

<u>Find the distance BC</u>

$B(6, 2),C(0, 8)$

Substitute the values in the formula

$d=\sqrt{(8-2)^{2}+(0-6)^{2}}$

$d=\sqrt{(6)^{2}+(-6)^{2}}$

$dBC=6\sqrt{2}\ units$

Step $3$

<u>Find the distance AC</u>

$A(-2, 2),C(0, 8)$

Substitute the values in the formula

$d=\sqrt{(8-2)^{2}+(0+2)^{2}}$

$d=\sqrt{(6)^{2}+(2)^{2}}$

$dAC=2\sqrt{10}\ units$

Step $4$

<u>Find the distance DC</u>

$D(0, 2),C(0, 8)$

Substitute the values in the formula

$d=\sqrt{(8-2)^{2}+(0-0)^{2}}$

$d=\sqrt{(6)^{2}+(0)^{2}}$

$dDC=6\ units$

Step $5$

<u>Find the perimeter of the triangle</u>

$P=AB+BC+AC$

substitute the values

$P=8\ units+6\sqrt{2}\ units+2\sqrt{10}\ units$

$P=22.81\ units$

therefore

The perimeter of the triangle is equal to $22.81\ units$

Step $6$

<u>Find the area of the triangle</u>

$A=\frac{1}{2}*base *heigth$

in this problem

$base=AB=8\ units\\heigth=DC=6\ units$

substitute the values

$A=\frac{1}{2}*8*6$

$A=24\ units^{2}$

therefore

the area of the triangle is $24\ units^{2}$

4 0

3 years ago

Read 2 more answers

Evaluate tan(cos^-1(-15/17))

IrinaK [193]

The answer is -8/15. This is a for sure correct answer.

7 0

3 years ago

Read 2 more answers

The function p(x) is an odd degree polynomial with a negative leading coefficient.

Aliun [14]

A because it’s the right answer

4 0

2 years ago