Answer:
y = x +3
Step-by-step explanation:
The equation of a parallel line can use the same x- and y-coefficients as the given equation. Only the constant needs to be found to make the line go through the given point.
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<h3>form of the solution</h3>
The equation of the given line is ...
y = x +4
So, the equation of a parallel line will be ...
y = x +b . . . . . for some y-intercept b
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<h3>solution</h3>
Using the given point (x, y) = (-1, 2), we can fill in the values and solve for b.
2 = -1 +b
3 = b . . . . . . add 1 to both sides
The desired equation is ...
y = x +3
Answer:
I think the 3rd option but im not sure
Must be 16 and 21 because we can see
30 and 70 has 10 as factor
24 and 44 has 2 as factor
12 and 30 has 2 as factor and all those factors are greater than one
Answer:
The launch angle should be adjusted to 30.63°
Step-by-step explanation:
The range of a projectile which is the horizontal distance covered by the projectile can be expressed as;
R =(v^2 sin2θ)/g
Where
R = range
v = initial speed
θ = launch angle
g = acceleration due to gravity
For the case above. When the projectile is launched at angle 13° above the horizontal.
θ1 = 13
R1 = (v^2 sin2θ1)/g
R1 = (v^2 sin26°)/g ....1
For the range to double
R2 = (v^2 sin2θ)/g .....2
R2 = 2R1
Substituting R2 and R1
(v^2 sin2θ)/g = 2 × (v^2 sin26°)/g
Divide both sides by v^2/g
sin2θ = 2sin26
2θ = sininverse(2sin26)
θ = sininverse(2sin26)/2
θ = 30.63°
I always find 10% of an amount , in your case I would then times the answer by 6. Half 10% and add them together- 10%=? 5%=? 60%=? 65%=?
