Answer:
13.89% of students are willing to report cheating by other students.
Step-by-step explanation:
We are given the following in the question:
Sample size, n = 180
Number of students who reported cheating, x = 25
We have to find the proportion of the students are willing to report cheating by other students.
Proportion of students can be calculate as

Thus, 13.89% of students are willing to report cheating by other students.
Answer:
y = 2
Step-by-step explanation:
The mid segment HJ is half of the third side GK , that is
HJ =
GK , substitute values
2y =
(y + 6) ← multiply both sides by 2 to clear the fraction
4y = y + 6 ( subtract y from both sides )
3y = 6 ( divide both sides by 3 )
y = 2
Answer: the third one
Step-by-step explanation: bcuz I’m Albert instine ;)
Answer:
x ≈ 3.1 ft
Step-by-step explanation:
The segment from the centre to the chord is a perpendicular bisector, thus
The triangle is right with base =
x
Applying Pythagoras' identity to the right triangle, then
(
x )² + 1.4² = 2.1²
x² + 1.96 = 4.41 ( subtract 1.96 from both sides )
x² = 2.45 ( multiply both sides by 4 )
x² = 9.8 ( take the square root of both sides )
x =
≈ 3.1 ft ( to the nearest tenth )
Answer: y = x^2 - 11x + 24
Step-by-step explanation: