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frosja888 [35]
3 years ago
11

An angle measures 57.2° less than the measure of a supplementary angle. What is the measure of each angle?

Mathematics
1 answer:
vagabundo [1.1K]3 years ago
5 0
<span>Straight lines measure 180°. That means that these two angles are supplementary.Complementary angles form a right angle (L shape) and have a sum of 90 degrees.</span>
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How would you justify that triangle G'H'I' is congruent to MNO?
Citrus2011 [14]

The triangle G'H'I' is congruent to MNO because they have two angles and the included side equal, therefore, the congruence criteria is ASA.

Answer: ASA

3 0
2 years ago
With full explanation from the internet like before<br> 3x2-6x+5=0
Elodia [21]

Answer:

\sf x=1+i\sqrt{\dfrac{2}{3}}   \ \quad and  \quad \:x=1-i\sqrt{\dfrac{2}{3}}

Explanation:

<u>Given Expression</u>:

  • 3x² - 6x + 5 = 0

Use the Quadratic Formula:

\sf x = \dfrac{ -b \pm \sqrt{b^2 - 4ac}}{2a}  \  \ when   \ \  ax^2 + bx + c = 0

<u>insert coefficients</u>

\Longrightarrow \sf x = \dfrac{-\left(-6\right)\pm \sqrt{\left(-6\right)^2-4\cdot \:3\cdot \:5}}{2\cdot \:3}

\Longrightarrow \sf x = \dfrac{\left6\right\pm \sqrt{-24} }{6}

\Longrightarrow \sf x = \dfrac{\left6\right\pm 2\sqrt{6}i}{6}

\Longrightarrow \sf x =1 \pm   i\dfrac{\sqrt{6} }{3}

\Longrightarrow \sf x=1+i\sqrt{\dfrac{2}{3}},  \quad 1-i\sqrt{\dfrac{2}{3}}

6 0
2 years ago
Read 2 more answers
Natalie completed 56 sit-ups. Natalie completed 4 times as many sit-ups as Matthew. How many sit-ups did Matthew complete?14 sit
REY [17]

Answer:

224 sit-ups

Step-by-step explanation:

multiply 56 by 4

8 0
3 years ago
Read 2 more answers
Real life example of parallelogram​
s344n2d4d5 [400]
Bag,laptop,book,wallet
5 0
3 years ago
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Suppose a solid is formed by revolving the function f(x)=2+mx around the x-axis where 0≤m&lt;1 and 0≤x≤1, and a washer is create
BabaBlast [244]

Answer:

(m³/3 + 5m/2 + 3)pi

Step-by-step explanation:

pi integral [(f(x))² - (g(x))²]

Limits 0 to 1

pi × integral [(2+mx)² - (1-mx)²]

pi × integral[4 + 4mx + m²x² - 1 + 2mx - m²x²]

pi × integral [m²x² + 5mx + 3]

pi × [m²x³/3 + 5mx²/2 + 3x]

Upper limit - lower limit

pi × [m²/3 + 5m/2 + 3]

Verification:

m = 0

[pi × 2² × 1] - [pi × 1² × 1] = 3pi

[m³/3 + 5m/2 + 3]pi

m = 0

3pi

3 0
3 years ago
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