Question

Work out the value of (root99-root11)^2 URGENT!!!!!

Answer 1

Answer:

$(\sqrt{99}-\sqrt{11})^2=44$

Step-by-step explanation:

$(\sqrt{99}-\sqrt{11})^2$

$(\sqrt{99}-\sqrt{11})(\sqrt{99}-\sqrt{11})$

$99-2\sqrt{99}\sqrt{11}+11$

$110-2\sqrt{99}\sqrt{11}$

$110-2\sqrt{9}\sqrt{11}\sqrt{11}$

$110-2(3)(11)$

$110-6(11)$

$110-66$

$44$