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Katyanochek1 [597]
2 years ago
11

Work out the value of (root99-root11)^2 URGENT!!!!!

Mathematics
1 answer:
maria [59]2 years ago
6 0

Answer:

(\sqrt{99}-\sqrt{11})^2=44

Step-by-step explanation:

(\sqrt{99}-\sqrt{11})^2

(\sqrt{99}-\sqrt{11})(\sqrt{99}-\sqrt{11})

99-2\sqrt{99}\sqrt{11}+11

110-2\sqrt{99}\sqrt{11}

110-2\sqrt{9}\sqrt{11}\sqrt{11}

110-2(3)(11)

110-6(11)

110-66

44

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What are the four answers?
Neko [114]

Answer:

CLAE

Step-by-step explanation:

1=43

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8 0
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10. Find the slope and y-intercept of the line.<br> y = 7/5x - 3
myrzilka [38]

Answer:

slope = 7/5

y-int = -3

Step-by-step explanation:

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8 0
3 years ago
Use the following image to assist in your answer.<br> a =<br> - 6<br> - 9<br> - 4
vfiekz [6]

Step-by-step explanation:

Pythagoras' theorem for the smallest one :

c^2 = 4^2 + 6^2

c^2 = 16 + 36

c^{2} = 52

Pythagoras' theorem for the middle one :

b^{2} = 6^{2} + a^{2}

Pythagoras' theorem for the biggest one :

(4+a)^2 = c^2 + b^2

16 + 8a + a^2 = 52 + b^2

Using the formula before (for b^2) it becomes :

16 + 8a + a^2 = 52 + (6^2 + a^2)

16 + 8a + a^2 = 52 + 6^2 + a^2

16 + 8a = 52 + 6^2

16 + 8a = 52 + 36

16+8a = 88

8a = 88-16

8a = 72

a = \frac{72}{8}

a = 9

Verifying :

b^2 = 6^2 + a^2

b^2 = 36 + 81

b^2 = 117

b^{2} = 117

The biggest one :

(4+a)^2 = c^2 + b^2

(4+9)^2 = 52 + 117

13^2 = 169

True

8 0
3 years ago
What is the solution to the inequality? -4/5x is greater than or equal to 1/10
Semenov [28]
-4x/5≥1/10
-8x≥1
x≤-1/8
x∈(-∞;-1/8]
6 0
3 years ago
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