All categories

1 year ago

Work out the value of (root99-root11)^2 URGENT!!!!!

Mathematics

1 answer:

maria [59]1 year ago

6 0

Answer:

$(\sqrt{99}-\sqrt{11})^2=44$

Step-by-step explanation:

$(\sqrt{99}-\sqrt{11})^2$

$(\sqrt{99}-\sqrt{11})(\sqrt{99}-\sqrt{11})$

$99-2\sqrt{99}\sqrt{11}+11$

$110-2\sqrt{99}\sqrt{11}$

$110-2\sqrt{9}\sqrt{11}\sqrt{11}$

$110-2(3)(11)$

$110-6(11)$

$110-66$

$44$

You might be interested in

If triangle JKL is classified as isosceles, which statement is true?

VMariaS [17]

Answer: At least two sides are congruent

Step-by-step explanation:

Here is the complete question:

If a triangle JKL is classified as isosceles, which statement is true?

a. At least two sides are congruent.

b. Two sides are perpendicular.

c. All three sides are congruent.

d. Two sides are parallel.

An isosceles triangle is a triangle that has at least two sides that are equal. An isosceles triangle has two equal sides and also two equal angles.

An angle is said to be congruent if it has the same angle either in degrees or radians. Such angles don't necessarily have to point in same direction. Therefore, it is true that at least two sides are congruent.

6 0

2 years ago

www.g The physical plant at the main campus of a large state university recieves daily requests to replace fluorescent lightbulb

damaskus [11]

Answer:

$z=\frac{24-40}{8}=-2$

$z=\frac{40-40}{8}=0$

And then the percentage between 24 and 40 would be $\frac{95}{2}= 47.5 \%$

Step-by-step explanation:

For this problem we have the following parameters given:

$\mu = 40, \sigma =8$

And for this case we want to find the percentage of lightbulb replacement requests numbering between 24 and 40.

From the empirical rule we know that we have 68% of the values within one deviation from the mean, 95% of the values within 2 deviations and 99.7% within 3 deviations.

We can find the number of deviations from themean for the limits with the z score formula we got:

$z=\frac{X-\mu}{\sigma}$