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Ganezh [65]
4 years ago
11

Write a two step equation involving division and addition that has a solution of x = 25

Mathematics
1 answer:
White raven [17]4 years ago
4 0
5x+10=25
5 divides into all the number to simplify to 3 plug in 3 into the x value then to multiply 5 and 3 which is 15 than add to to equal 25
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Plz help with with this math problem
beks73 [17]

Answer:

x=50

Step-by-step explanation:

Because 10x5 equals 50

4 0
3 years ago
Read 2 more answers
there are five exams. the student earned grades 84,75,97, and 89 for the first four exams.what grade must the student earn pm th
emmasim [6.3K]

Answer:

81

Step-by-step explanation:

Given total number of tests are 5

The grades earned by the students in the tests are 84 , 75 , 97 , 89

let the grade earned by the student in the fifth test be x.

Average=\frac{84+75+97+89+x}{5}

The condition recquired is Average≥85

\frac{84+75+97+89+x}{5}≥85

\frac{344+x}{5}≥85

x+344≥425

x≥81.

The least grade the student can earn in the last test so that average is not less than 85 is 81

4 0
3 years ago
What is the midpoint between (-4 - 2i) and ( 6 + 8i) on the complex plane?
diamong [38]
Add the real parts and the imaginary parts separately and divide each by 2


= (  \frac{ - 4 + 6}{2}  +   \frac{ - 2i + 8i}{2} )


= ( \frac{2}{2}  +  \frac{6i}{2} )


=(1+3i)

5 0
3 years ago
5 women and 7 men are eligible to serve on a committee. If a committee of 4 is randomly selected, what is the probability that i
rosijanka [135]

Answer:

The required  probability is \frac{14}{33}.

Step-by-step explanation:

Probability:

The ratio of the favorable outcomes to the all possible outcomes.

Given that, 5 women and 7 men are eligible to serve on a committee.

A committee of 4 is randomly selected.

Choosing 2 women out of 5 women is

=^5C_2

=\frac{5!}{2!(5-2)!}

=\frac{5!}{2!3!}

=10

Choosing 2 men out of 7 men is

=^7C_2

=\frac{7!}{2!(7-2)!}

=\frac{7!}{2!5!}

=21

Total number of eligible person is = (5+7)=12

Choosing 4 member out of 12 member is

=^{12}C_4

=\frac{12!}{4!(12-4)!}

=495

The required  probability is

=\frac{10\times 21}{495}

=\frac{14}{33}

7 0
3 years ago
What is the difference between -3 and five a number line
vfiekz [6]
The answer to you’re question is 8
8 0
4 years ago
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