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Minchanka [31]
3 years ago
7

What is 18k + 30fk in like terms. Will give brainliest to correct answer.

Mathematics
2 answers:
oee [108]3 years ago
4 0

Answer:

6k(5f+3)

Step-by-step explanation:

18k+30fk

Factor out 6.

6(3k+5fk)

Consider 3k+5fk. Factor out k.

k(3+5f)

Rewrite the complete factored expression.

6k(5f+3)

zloy xaker [14]3 years ago
4 0

Answer:

6k(5f+3)

Step-by-step explanation:

18k+30fk

Factor out 6.

6(3k+5fk)

Consider 3k+5fk. Factor out k.

k(3+5f)

Rewrite the complete factored expression.

6k(5f+3)

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To the nearest​ millimeter, a cell phone is 114 mm long and 69 mm wide. What is the ratio of the width to the​ length
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69mm:114 mm

Step-by-step explanation:

8 0
2 years ago
Write an expression to represent "the sum of triple a number and fifteen."
lana66690 [7]
The sum is adding
3 times a number is 3x
And 15 is +15
3x+15
3 0
3 years ago
Find a number C such that the polynomial p(x)= -x+4x^2+Cx^3-8x^4
Ksenya-84 [330]

Answer:

C = 2

Step-by-step explanation:

p(x)= -x+4x^2+Cx^3-8x^4 \\  \\  \because \: given \: polynmial \: has \: zero \: at \: \\x =  \frac{1}{4}  \\  \\  \implies \: p\bigg(\frac{1}{4}  \bigg) = 0...(1) \\  \\ plug \: x = \frac{1}{4} \:  in \: p(x) \: we \: find \\  \\ p \bigg(\frac{1}{4}  \bigg)  =  - \frac{1}{4} + 4  {\bigg(\frac{1}{4} \bigg)}^{2}  + c  {\bigg(\frac{1}{4} \bigg)}^{3}  - 8  {\bigg(\frac{1}{4} \bigg)}^{4}  \\  \\ 0 = - \frac{1}{4} + \cancel 4 \times   {\frac{1}{\cancel{16} } }  + c  {\bigg(\frac{1}{64} \bigg)}  - \cancel 8  \times  \frac{1}{\cancel{256} }  \\  \\0 =\cancel{ - \frac{1}{4}} + \cancel  {{\frac{1}{4} }}  + c  {\bigg(\frac{1}{64} \bigg)}  -  \times  \frac{1}{32}  \\  \\0 =  c  {\bigg(\frac{1}{64} \bigg)}  -  \frac{1}{32}  \\  \\c  {\bigg(\frac{1}{64} \bigg)} = \frac{1}{32}   \\  \\ c = \frac{1}{32}   \times 64 \\  \\ c = 2

5 0
3 years ago
!!!!HELP NEEDED!!!!
Svetllana [295]

It is true that the product of two consecutive even integers are always one less than the square of their average.

<u>Step-by-step explanation</u>:

Let the two consecutive odd integers be 1 and 3.

  • The product of 1 and 3 is (1\times3)=3
  • The average of 1 and 3 is (1+3)/2 =4/2 = 2
  • The square of their average is (2)² = 4

∴ The product 3 is one less than the square of their average 4.

Let the two consecutive even integers be 2 and 4.

  • The product of 2 and 4 is (2\times4)=8
  • The average of 2 and 4 is (2+4)/2 =6/2 = 3
  • The square of their average is (3)² = 9

∴ The product 8 is one less than the square of their average 9.

Thus, It is true that the product of two consecutive even integers are always one less than the square of their average.

4 0
3 years ago
Help! I’ll mark you brainly and give extra points!!
irina1246 [14]

Answer:

Slope: 2

y-intercept: (0, -4)

x           y

0          -4

2           0

Hope this helps! Can I have Brainliest please?

See attachment below:

8 0
3 years ago
Read 2 more answers
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