All categories

3 years ago

What is 18k + 30fk in like terms. Will give brainliest to correct answer.

Mathematics

2 answers:

oee [108]3 years ago

4 0

Answer:

6k(5f+3)

Step-by-step explanation:

18k+30fk

Factor out 6.

6(3k+5fk)

Consider 3k+5fk. Factor out k.

k(3+5f)

Rewrite the complete factored expression.

6k(5f+3)

zloy xaker [14]3 years ago

4 0

Answer:

6k(5f+3)

Step-by-step explanation:

18k+30fk

Factor out 6.

6(3k+5fk)

Consider 3k+5fk. Factor out k.

k(3+5f)

Rewrite the complete factored expression.

6k(5f+3)

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Solve the system of equations algebraically show all work. Y=-x^2+8x+11 Y=5x-7

morpeh [17]

Answer:

ummmm..... let's see..

Step-by-step explanation:

using "Almighty formula"

{Y = –x +/– √b^2 – 4ac / 2a}

so we name all the values behind the coefficients which are; –1^2, 8 and 11

so let's assign a,b,c to these values:

a =–1, b =8, c = 11

all you just do now is to add these values to the formula

you should be having Y =1 +/– √8^2 – 4×–1×11

———————————

2×–1

Y =1 +108

———— or Y = 1–108

–2 –––––

–2

now add and divide to get Y.

(your answer will be two)

5 0

2 years ago

The equation of line CD is Y=3X -3. Write an equation of a line perpendicular to line CD in slope intercept form that contains p

OLga [1]

(I'm learning this right now!)

y = 3x - 3
If a line is perpendicular to another line, they have negative reciprocal slopes.
So you would use the slope -1/3.

Use y - y₁ = m(x - x₁) to get an equation in slope intercept form.
Plug the numbers in.

y - 1 = -1/3(x - 3)
y - 1 = -1/3x + 1
y = -1/3x + 2

An equation of a line perpendicular to line CD is y = -1/3x + 2.

8 0

3 years ago

Please give a step-by-step solution of 2x^2 +12x = 6 (by completing the square)

sp2606 [1]

Answer:

x = - 3 ± 2 $\sqrt{3}$

Step-by-step explanation:

Given

2x² + 12x = 6 ( divide through by 2 )

x² + 6x = 3

To complete the square

add ( half the coefficient of the x- term )² to both sides

x² + 2(3)x + 9 = 3 + 9

(x + 3)² = 12 ( take the square root of both sides )

x + 3 = ± $\sqrt{12}$ = ± 2 $\sqrt{3}$ ( subtract 3 from both sides )

x = - 3 ± 2 $\sqrt{3}$ ← exact solutions

6 0

3 years ago

Noah wants to clean his second story windows and plans to buy a ladder that will reach at least

Lina20 [59]

Answer:

Noah should buy a ladder of length greater than 28.1 ft to reach at least 22 feet height.

Step-by-step explanation:

Given:

Noah has to reach at least 22 ft height.

Angle made by the base of ladder with the ground = 51.5°

To find the length of the ladder.

Solution:

On drawing the situation, we get a right triangle. The hypotenuse of the triangle represents the length of the ladder.

In triangle ABC.

∠C = 51.5°

AB = 22 ft

Applying trigonometric ratio to find AC (length of the ladder).

$\sin\theta = \frac{Opposite\ side}{Hypotenuse}$

$\sin C=\frac{AB}{AC}$

Plugging in values.

$\sin 51.5\°=\frac{22}{AC}$

Multiplying AC both sides.

$AC\sin 51.5\°=\frac{22}{AC}\times AC$

$AC\sin 51.5\°=22$

Dividing both sides by $\sin 51.5\°$

$\frac{AC\sin 51.5\°}{\sin 51.5\°}=\frac{22}{\sin 51.5\°}$

$AC=\frac{22}{\sin 51.5\°}$

$AC=28.1\ ft$

Thus, Noah should buy a ladder of length greater than 28.1 ft to reach at least 22 feet height.

5 0

3 years ago

<img src="https://tex.z-dn.net/?f=f%28x%29%20%3D%20%5Cfrac%7B%282x%2B1%29%28x-5%29%7D%7B%28x-5%29%28x%2B4%29%5E%7B2%7D%20%7D" id

dybincka [34]

i) The given function is

$f(x)=\frac{(2x+1)(x-5)}{(x-5)(x+4)^2}$

The domain is

$(x-5)(x+4)^2\ne 0$

$(x-5)\ne0,(x+4)^2\ne 0$

$x\ne5,x\ne -4$

ii) For vertical asymptotes, we simplify the function to get;

$f(x)=\frac{(2x+1)}{(x+4)^2}$

The vertical asymptote occurs at

$(x+4)^2=0$

$x=-4$

iii) The roots are the x-intercepts of the reduced fraction.

Equate the numerator of the reduced fraction to zero.

$2x+1=0$

$2x=-1$

$x=-\frac{1}{2}$

iv) To find the y-intercept, we substitute $x=0$ into the reduced fraction.

$f(0)=\frac{(2(0)+1)}{(0+4)^2}$

$f(0)=\frac{(1)}{(4)^2}$

$f(0)=\frac{1}{16}$

v) The horizontal asymptote is given by;

$lim_{x\to \infty}\frac{(2x+1)}{(x+4)^2}=0$

The horizontal asymptote is $y=0$ .

vi) The function has a hole at $x-5=0$ .

Thus at $x=5$ .

This is the factor common to both the numerator and the denominator.

vii) The function is a proper rational function.

Proper rational functions do not have oblique asymptotes.

6 0

3 years ago