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Archy [21]
3 years ago
5

Help find the measure of the angle indicated!!!?

Mathematics
1 answer:
Alecsey [184]3 years ago
8 0

Answer:

50°

Step-by-step explanation:

m\angle RST = \frac{1}{2} \times (150\degree - 50\degree) \\\\m\angle RST = \frac{1}{2} \times 100\degree \\\\ \purple{ \bold{m\angle RST =50\degree}} \\\\

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Can you put 5(3+j+2j) as a verbal expression?
liraira [26]

"Five times the sum of three, J, and two times J."

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Why would you want to? The math expression is much more concise and less likely to be misinterpreted.

5 0
4 years ago
Please help and thank you
djyliett [7]

The answer would be D

G(x) = (X-4)^2

8 0
3 years ago
Read 2 more answers
FILL IN THE BLANK TO MAKE THE NUMBER SENTENCE TRUE.<br><br> 6 X 2/<br> = 6
mel-nik [20]
6 x 2/2 = 6, because 2/2 is 1 and 6x1 is 6
3 0
3 years ago
Jess made 3 different stacks of wooden blocks. The first stack was 8 blocks high ,the second stack was 4 blocks higher than the
kirill [66]

Answer:

Jess used 40 blocks in total.

Step-by-step explanation:

First stack: 8 blocks

Second stack: First stack + 4 = 8 + 4 = 12 blocks

Third stack: Second stack + 8 = 12 + 8 = 20 blocks

Total number of blocks: First stack + Second stack + Third stack = 8 + 12 + 20 = 40 blocks

3 0
3 years ago
I need help proving this ASAP
Ket [755]

Answer:

See explanation

Step-by-step explanation:

We want to show that:

\tan(x +  \frac{3\pi}{2} )  =  -   \cot \: x

One way is to use the basic double angle formula:

\frac{ \sin(x +  \frac{3\pi}{2} ) }{\cos(x +  \frac{3\pi}{2} )}  =  \frac{ \sin(x)  \cos( \frac{3\pi}{2} )  +   \cos(x)  \sin( \frac{3\pi}{2}) }{\cos(x)  \cos( \frac{3\pi}{2} )   -    \sin(x)  \sin( \frac{3\pi}{2}) }

\frac{ \sin(x +  \frac{3\pi}{2} ) }{\cos(x +  \frac{3\pi}{2} )}  =  \frac{ \sin(x) ( 0)  +   \cos(x) (  - 1) }{\cos(x) (0)   -    \sin(x) (  - 1) }

We simplify further to get:

\frac{ \sin(x +  \frac{3\pi}{2} ) }{\cos(x +  \frac{3\pi}{2} )}  =  \frac{ 0  -   \cos(x) }{0 +    \sin(x) }

We simplify again to get;

\frac{ \sin(x +  \frac{3\pi}{2} ) }{\cos(x +  \frac{3\pi}{2} )}  =  \frac{- \cos(x) }{ \sin(x) }

This finally gives:

\frac{ \sin(x +  \frac{3\pi}{2} ) }{\cos(x +  \frac{3\pi}{2} )}  =  -  \cot(x)

6 0
4 years ago
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