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Travka [436]
3 years ago
5

Mrs Williams has 30 students in her class 12 of her students are boys what percent of Mrs Williams students are boys

Mathematics
2 answers:
photoshop1234 [79]3 years ago
8 0
30 divided by 12 equals 2.5 so it should equal 2.5%
aleksley [76]3 years ago
4 0
12 out of 30 students are boys, so you can also say 12/30. 12/30 simplified is 4/10, or 40%.
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A group of friends chartered a deep-sea fishing boat out of destin, fl. the graph below represents the total cost, in dollars, o
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The difference in price per passenger for a group of 16 versus a group of 10 is $26.25

<h3>What is an equation?</h3>

An equation is an expression that shows the relationship between two or more number and variables.

From the graph:

The cost for a group of 16 friends is $2500, while for a group of 10 friends is $1300.

Cost per passenger for 16 friend = $2500 / 16 = $156.25

Cost per passenger for 10 friend = $1300 / 10 = $130

The difference in price = $156.25 - $130 = $26.25

The difference in price per passenger for a group of 16 versus a group of 10 is $26.25

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Answer:

0.1

Step-by-step explanation:

Solving using empirical rule formula

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μ - 2σ

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= 0.2 - 2(0.05)

= 0.2 - 0.1

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6 0
3 years ago
A student draws a triangle with a perimeter of 36cm. The student says the longest length is 18cm. How do you know the student is
Crazy boy [7]

The length of the first two sides of a triangle must be greater than the length of the last side.  If the longest length were 18, the first two sides would be too short.  36-18=18, 18 is equal not greater than 18 which means the sum of the first two sides are too short.

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3 years ago
Evaluate the triple integral ∭EzdV where E is the solid bounded by the cylinder y2+z2=81 and the planes x=0,y=9x and z=0 in the
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Answer:

I = 91.125

Step-by-step explanation:

Given that:

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The initial activity to carry out is to determine the limits of the region

since curve z = 0 and y^2 + z^2 = 81

∴ z^2 = 81 - y^2

z = \sqrt{81 - y^2}

Thus, z lies between 0 to \sqrt{81 - y^2}

GIven curve x = 0 and y = 9x

x =\dfrac{y}{9}

As such,x lies between 0 to \dfrac{y}{9}

Given curve x = 0 , x =\dfrac{y}{9} and z = 0, y^2 + z^2 = 81

y = 0 and

y^2 = 81 \\ \\ y = \sqrt{81}  \\ \\  y = 9

∴ y lies between 0 and 9

Then I = \int^9_{y=0} \int^{\dfrac{y}{9}}_{x=0} \int^{\sqrt{81-y^2}}_{z=0} \ zdzdxdy

I = \int^9_{y=0} \int^{\dfrac{y}{9}}_{x=0} \begin {bmatrix} \dfrac{z^2}{2} \end {bmatrix}    ^ {\sqrt {{81-y^2}}}_{0} \ dxdy

I = \int^9_{y=0} \int^{\dfrac{y}{9}}_{x=0} \begin {bmatrix}  \dfrac{(\sqrt{81 -y^2})^2 }{2}-0  \end {bmatrix}     \ dxdy

I = \int^9_{y=0} \int^{\dfrac{y}{9}}_{x=0} \begin {bmatrix}  \dfrac{{81 -y^2} }{2} \end {bmatrix}     \ dxdy

I = \int^9_{y=0}  \begin {bmatrix}  \dfrac{{81x -xy^2} }{2} \end {bmatrix} ^{\dfrac{y}{9}}_{0}    \ dy

I = \int^9_{y=0}  \begin {bmatrix}  \dfrac{{81(\dfrac{y}{9}) -(\dfrac{y}{9})y^2} }{2}-0 \end {bmatrix}     \ dy

I = \int^9_{y=0}  \begin {bmatrix}  \dfrac{{81 \  y -y^3} }{18} \end {bmatrix}     \ dy

I = \dfrac{1}{18} \int^9_{y=0}  \begin {bmatrix}  {81 \  y -y^3}  \end {bmatrix}     \ dy

I = \dfrac{1}{18}  \begin {bmatrix}  {81 \ \dfrac{y^2}{2} - \dfrac{y^4}{4}}  \end {bmatrix}^9_0

I = \dfrac{1}{18}  \begin {bmatrix}  {40.5 \ (9^2) - \dfrac{9^4}{4}}  \end {bmatrix}

I = \dfrac{1}{18}  \begin {bmatrix}  3280.5 - 1640.25  \end {bmatrix}

I = \dfrac{1}{18}  \begin {bmatrix}  1640.25  \end {bmatrix}

I = 91.125

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3 years ago
Find the Factors of 84.
polet [3.4K]
84 is a composite number. 84 = 1 x 84, 2 x 42, 3 x 28, 4 x 21, 6 x 14, or 7 x 12.
Factors of 84: 1, 2, 3, 4, 6, 7, 12, 14, 21, 28, 42, 84.
7 0
3 years ago
Read 2 more answers
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