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3 years ago

Mrs Williams has 30 students in her class 12 of her students are boys what percent of Mrs Williams students are boys

Mathematics

2 answers:

photoshop1234 [79]3 years ago

8 0

30 divided by 12 equals 2.5 so it should equal 2.5%

aleksley [76]3 years ago

4 0

12 out of 30 students are boys, so you can also say 12/30. 12/30 simplified is 4/10, or 40%.

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All of the following are ways to write 25 percent of N EXCEPT 0.25N 25N/100 1/4N 25N

Olin [163]

The last one would be incorrect. We are looking for PART of whatever N is. Multiply by the whole number 25 is definitely not what we want to do.

Hope I helped!

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3 years ago

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PLEASE HELP WITH THIS

kobusy [5.1K]

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3 years ago

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Pls halp list four nonzero multiples of 2 6 9 12 25 90

Simora [160]

Multiples of 2: 2,4,6,8

Multiples of 6:6,12,18,24

Multiples of 12:12,24,36,48

Multiples of 25:25,50,75,100

Further explanation:

A multiple is a number that is obtained by multiplying an integer with that number.

We have to find multiples of given numbers:

So,

1. Multiples of 2

$Four\ non-zero\ Multiples\ of\ 2: 2,4,6,8$

2. Multiples of 6

$Four\ non-zero\ Multiples\ of\ 6: 6,12,18,24$

3. Multiples of 12

$Four\ non-zero\ Multiples\ of\ 12: 12,24,36,48$

4. Multiples of 25

$Four\ non-zero\ Multiples\ of\ 25: 25,50,75,100$

Keywords: Multiples, Non-zero multiples

Learn more about multiples at:

#LearnwithBrainly

5 0

3 years ago

I need help! Will mark Brainliest for full answer!!!

Softa [21]

Answer:

Part a .............> x = 11

Part b .............> k = 57.2

Part c .............> y = 9.2

Explanation:

The three problems deal with inverse variation between two variables

An inverse variation relation between two variables means that when one of the variables increases, the other will decrease (and vice versa)

Mathematically, an inverse variation relation is represented as follows:

$y = \frac{k}{x}$

where x and y are the two variables and k is the constant of variation

Now, let's check the givens:

Part a:

We are given that y = 3 and k = 33

Substitute in the original relation and solve for x as follows:

$y = \frac{k}{x}\\ \\3 = \frac{33}{x}\\ \\x=\frac{33}{3}=11$

Part b:

We are given that y = 11 and x = 5.2

Substitute in the original relation and solve for k as follows:

$y=\frac{k}{x}\\ \\11=\frac{k}{5.2}\\ \\k=11*5.2=57.2$

Part c:

We are given that x=7.8 and k=72

Substitute in the original relation and solve for y as follows:

$y=\frac{k}{x}=\frac{72}{7.8}=9.2$ to the nearest tenth

Hope this helps :)

6 0

3 years ago

What is the area of a right triangle with a hypotenuse of 12 and 1 leg is 10??

Agata [3.3K]

Hey there! :)

Area of triangles → (base × height) ÷ 2

The base and height are the 2 legs. You have to find the length of the other leg to find the area, using the Pythagorean Theorem.

a² + b² = c² → c² - a² = b²

c = 12
12² = 12 × 12 = 144

a = 10
10² = 10 × 10 = 100

144 - 100 = 44

√44 = 6.6
_____________________________________________________________

Area of triangles → (base × height) ÷ 2

Base: 10
Height: 6.6

6.6 × 10 = 66

66 ÷ 2 = 33

The area is 33

Hope this helps :)

5 0

3 years ago