All categories

2 years ago

Pls halplist four nonzero multiples of269122590

Mathematics

1 answer:

Simora [160]2 years ago

5 0

Multiples of 2: 2,4,6,8

Multiples of 6:6,12,18,24

Multiples of 12:12,24,36,48

Multiples of 25:25,50,75,100

Further explanation:

A multiple is a number that is obtained by multiplying an integer with that number.

We have to find multiples of given numbers:

So,

1. Multiples of 2

$Four\ non-zero\ Multiples\ of\ 2: 2,4,6,8$

2. Multiples of 6

$Four\ non-zero\ Multiples\ of\ 6: 6,12,18,24$

3. Multiples of 12

$Four\ non-zero\ Multiples\ of\ 12: 12,24,36,48$

4. Multiples of 25

$Four\ non-zero\ Multiples\ of\ 25: 25,50,75,100$

Keywords: Multiples, Non-zero multiples

Learn more about multiples at:

#LearnwithBrainly

You might be interested in

What is 2/3 plus 11/12 equal in a fraction

dlinn [17]

19/12

welcome :):):):)

6 0

2 years ago

Read 2 more answers

F(x) = 8|x| - 5 f(-2) =

Anastaziya [24]

Answer:

f(-2) = 11

Step-by-step explanation:

Hello!

We can evaluate y by plugging in -2 for x in the equation.

<h3>Evaluate</h3>

f(x) = 8|x| - 5
f(-2) = 8|-2| - 5
f(-2) = 8(2) - 5 Remember that absolute value turns the number positive
f(-2) = 16 - 5
f(-2) = 11

The evaluated value is 11.

6 0

1 year ago

Point A lies outside of plane P. How many lines can be drawn perpendicular to plane P through point A?

Ivanshal [37]

Answer

D) 1

Explanation

A perpendicular line makes a angle of 90° with a line or a plane.

If a line is to be drawn from a point to a line or a plain it can only be one. In this case a line is to be drawn through a point A to a plane P. If the line is to be perpendicular, then is is only one.

From the choices, the appropriate answer is D) 1

3 0

2 years ago

Read 2 more answers

Consider the function f ( x ) = − 2 x 3 + 27 x 2 − 108 x + 9 . For this function there are three important open intervals: ( − [

Darya [45]

Answer:

A=3 and B=6

Step-by-step explanation:

Increasing and Decreasing Intervals of Functions

Given f(x) as a real function and f'(x) its first derivative.

If f'(a)>0 the function is increasing in x=a

If f'(a)<0 the function is decreasing in x=a

If f'(a)=0 the function has a critical point in x=a

As we can see, the critical points may define open intervals where the function has different behaviors.

We have

$f ( x ) = - 2 x^3 + 27 x^2 - 108 x + 9$

Computing the first derivative:

$f' ( x ) = - 6 x^3 + 54 x - 108$

We find the critical points equating f'(x) to zero

$- 6 x^3 + 54 x - 108=0$

Simplifying by -6

$x^2 -9 x +18=0$

We get the critical points

$x=3,\ x=6$

They define the following intervals

$(-\infty,3),\ (3,6),\ (6,+\infty)$

Thus A=3 and B=6

3 0

3 years ago

A stack of magazines is 4 2/5 inches high. The stack needs to fit into a box that is 2 1/8 inches high. How many inches too high

iren [92.7K]

Answer: Equation: 4 $\frac{2}{5}$ -2 $\frac{1}{8}$ ; estimate: a

little more than 2 inches; answer: 2 $\frac{11}{40}$

inches.

Step-by-step explanation:

6 0

2 years ago

Read 2 more answers

Pls halplist four nonzero multiples of269122590​

Pls halplist four nonzero multiples of269122590