Answer:
8 portraits are going to be used in the display.
Step-by-step explanation:
This problem can be solved as a rule of three problem.
Each yd has 36 inches.
The display is to span a total width of 10 yd. So it is a total width of 360 inches.
Each portrait has a width of 45 in. How many portraits can there be?
1 portrait - 45 in
x portraits - 360 in


8 portraits are going to be used in the display.
Let the hall be A=1. For 3 hours 16 people can decorate the hall. Then P1=A\(t1.number people1) P=1/48. That is for 1 person. You have 24 people to decorate the same hall. Their P2 will be (1/48).24=1/2. t2=A/P2=2 hours
Answer: B
Step-by-step explanation: x = 6