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Marizza181 [45]
3 years ago
15

Please help with my math ​

Mathematics
1 answer:
GuDViN [60]3 years ago
6 0

Answer:

its 80

...............

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I need help with #11
Troyanec [42]
\bf \qquad \qquad \qquad \qquad \textit{function transformations}
\\ \quad \\\\

\begin{array}{rllll} 
% left side templates
f(x)=&{{  A}}({{  B}}x+{{  C}})+{{  D}}
\\ \quad \\
y=&{{  A}}({{  B}}x+{{  C}})+{{  D}}
\\ \quad \\
f(x)=&{{  A}}\sqrt{{{  B}}x+{{  C}}}+{{  D}}
\\ \quad \\
f(x)=&{{  A}}(\mathbb{R})^{{{  B}}x+{{  C}}}+{{  D}}
\\ \quad \\
f(x)=&{{  A}} sin\left({{ B }}x+{{  C}}  \right)+{{  D}}
\end{array}

\bf \begin{array}{llll}
% right side info
\bullet \textit{ stretches or shrinks horizontally by  } {{  A}}\cdot {{  B}}\\\\
\bullet \textit{ flips it upside-down if }{{  A}}\textit{ is negative}
\\\\
\bullet \textit{ horizontal shift by }\frac{{{  C}}}{{{  B}}}\\
\qquad  if\ \frac{{{  C}}}{{{  B}}}\textit{ is negative, to the right}\\\\
\qquad  if\ \frac{{{  C}}}{{{  B}}}\textit{ is positive, to the left}\\\\
\end{array}

\bf \begin{array}{llll}


\bullet \textit{ vertical shift by }{{  D}}\\
\qquad if\ {{  D}}\textit{ is negative, downwards}\\\\
\qquad if\ {{  D}}\textit{ is positive, upwards}\\\\
\bullet \textit{ period of }\frac{2\pi }{{{  B}}}
\end{array}

now, with that template in mind, let's take a peek at this function

\bf \begin{array}{lllcclll}
y=&2(&1x&-2)^2&-4\\
&\uparrow &\uparrow &\uparrow &\uparrow \\
&A&B&C&D
\end{array}\\\\
-----------------------------\\\\
A\cdot B=2\impliedby \textit{shrunk by a factor of 2, of half-size}\\\\
\cfrac{C}{B}= \cfrac{-2}{1}\implies -2\impliedby \textit{horizontal right shift of 2 units}\\\\
D=-4\impliedby \textit{vertical down shift of 4 units}

so, the graph of y=2(x-2)²-4, is really the same graph of y=x², BUT, narrower, and moved about horizontally and vertically
8 0
3 years ago
Read 2 more answers
Expand <br><br> 2y (2y + 8 )
Andrews [41]
Hello There!

2y x 2y = 4y²
2y x 8 = 16y.
Put it together and you get the answer of:
4y² + 16y.

Hope This Helps You!
Good Luck :) 

- Hannah ❤
7 0
3 years ago
If T(n) = 3n -5 what is the 3rd term
PtichkaEL [24]
Tn=3n-5 therefore: T(3)=3(3)-5 T(3) =4
4 0
3 years ago
An empty 5-gal water jug weighs 0.75 lb. With 3 c of water inside, the jug weighs 2.25 lb. Which equation models the jug's weigh
Deffense [45]
Weight of 1 c
3 c = 2.25 - empty bucket
3 c = 2.25 - 0.75
3 c = 1.5
c = 1.5/3 =1/2

Jug Weigh = (1/2)x +0.75
8 0
3 years ago
Mrs. Fronkos class for evry 6 boys there are 8 girls. Write the ratio of boys to girls in simplest form
Rama09 [41]

Answer:

3:4

Step-by-step explanation:

there are 6 boys for every 8 girls, so the initial ratio is 6:8. however, this can be simplified by finding a number both 6 and 8 are evenly divisible by. In this case, you can divide the ratio by 2. 6/2 = 3 and 8/2 = 4, which is why the simplified form is 3:4

5 0
3 years ago
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