For the first one c-9=(2)(4)+6
You are gonna multiply 2 and 4 first, 2*4=8. Now you have c-9=8+6. 8+6=14. So now the equation is c-9=14. Now we are going to add 9 to both sides. So c=23
For the second equation 10+y=90. We are going to subtract 10 from both sides. So, y=80.
Third, add 4 to both sides. a=10.
Fourth, subtract 8 from both sides. d=-9
Fifth, 5+2(3+4)=-x.
First we are going to add 3 and 4. 3+4=7. 5+2(7)=-x. Next we are going to multiply 2 and 7. 2*7=14. 5+14=-x. 5+14=19. So our equation is 19=-x. Next we are going to multiply both sides by -1. Making our final equation x=-19.
c=23
y=80
a=10
d=-9
x=-19
I hope that helps, if you need any further explanation just ask.<span />
What is it? I will help. :)
Answer:
11:13
Step-by-step explanation:
132:156
Split in half
66:78
Again
33:39
By 3
11:13
Answer
65-44.78>4
I hope this helps:)
Answer:
- solutions: (2, 10), (4, 5)
- non-solutions: all other points
Step-by-step explanation:
It can be useful to graph the inequalities related to Tyler's limits of money and weight.
1x +3y ≤ 36 . . . . . . the limit on the cost of the items Tyler can afford
1x +1.5y ≤ 20 . . . . . the limit on the weight of the items Tyler can carry
Then plotting the given points shows that only (2, 10) and (4, 5) are in the doubly-shaded area that is the solution space. The other points are not a solution.
