1700 J of energy is lost from 0.14 kg object , the temperature decreases from 50°C to 45°C what is the specific heat of this obj
1 answer:
You might be interested in
The picture shows it has a real life something to display conservation of energy with kinetic energy and potential energy.
Five sentences are for potential and kinetic energy. Potential energy is to energy an object when it stores. Kinetic energy is something to motion. When the potential energy is slows down the potential energy it might be increases. As from the object when the speeds up and it is decreases to potential energy.
Kinetic energy is to calculated by KE= mass×velocity²/2 as a fraction.
Potential energy is to calculated by PE= mass×g×height.
And the another picture it has a <span>energy, kinetic energy, mechanical energy, conservation of energy.
</span>
Five sentences are for potential and kinetic energy. Potential energy is to energy an object when it stores. Kinetic energy is something to motion. When the potential energy is slows down the potential energy it might be increases. As from the object when the speeds up and it is decreases to potential energy.
Kinetic energy is to calculated by KE= mass×velocity²/2 as a fraction.
Potential energy is to calculated by PE= mass×g×height.
And the another picture it has a <span>energy, kinetic energy, mechanical energy, conservation of energy.
</span>
Explanation:
Given parameters:
Distance = 15miles north = 24140.2m
Initial velocity = 0m/s
Final velocity = 4m/s
Unknown:
Speed, velocity and acceleration = ?
Solution:
The speed is the distance divide by time. It is a scalar quantity and has no directional attribute.
Speed =
The speed of the student is 4m/s
Velocity is the displacement divided by time. It is a vector quantity which specifies the direction and magnitude;
Velocity =
The velocity of the student is 4m/s due north
Acceleration is the change in velocity with time;
To find the acceleration, we use
v² = u² + 2as
v is the final velocity
u is the initial velocity
a is the acceleration
s is the distance
4² = 0² + 2x a x 24140.2
a = = 0.00033m/s²