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Amiraneli [1.4K]
4 years ago
14

What device is used to measure the current in a circuit

Physics
1 answer:
Natalka [10]4 years ago
8 0
The device is called the ammeter 
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Calculate the speed of an object that moves 200 m in 4 s?
Rasek [7]
50m/s

I divided the 200m by 4s (so 200/4) to get 50m per second
7 0
3 years ago
See the person on the right side of the front car. Six reference points could be used to show that the person is in / is NOT in
Rasek [7]

▪▪▪▪▪▪▪▪▪▪▪▪▪  {\huge\mathfrak{Answer}}▪▪▪▪▪▪▪▪▪▪▪▪▪▪

1. According to person standing on ground ~

  • The person is in motion

2. According to The car ~

  • The person is not in motion

3. According to the Seat ~

  • The person is not in motion

4. According to another person on ride ~

  • The person is not in motion

5. According to the track ~

  • The person is in motion

6. According to the Sun ~

  • The person is in motion

I hope that's what you were looking for, goodluck for your assignment ~

7 0
2 years ago
The graph represents velocity over time.<br> What is the acceleration?
Semmy [17]

Answer:

I think the answer is 0.2 m/s2

Explanation:

7 0
2 years ago
Consider a coin which is tossed straight up into the air. After it is released it moves upward, reaches its highest point and fa
avanturin [10]

Answer:

GRAVITATIONAL FORCE

Explanation:

We may have noticed that a body thrown upward in air falls back down again after attaining a particular height. The object was able to fall down back due to the effect of gravity acting on it. If there are no force of gravity acting on the body, the body will not fall back but rather disappears into the thin air.

A coin tossed upward in the air which falls back down when released is therefore under the influence of gravity i.e GRAVITATIONAL FORCE while it moves upward after it is released

3 0
3 years ago
A race car reaches the finish line and the driver slows down to come to a stop. If it takes the car 10 seconds to stop at a cons
boyakko [2]

Answer:

53.64 m/s

Explanation:

Applying,

a = (v-u)/t............. Equation 1

Where a = acceleration of the car, v = final velocity of the car, u = initial velocity of the car, t = time.

make u the subject of the equation

u = v-at............. Equation 2

From the question,

Given: a = -12 mph/s = -5.364 m/s², t = 10 seconds, v = 0 m/s (comes to stop)

Substitute these values into equation 2

u = 0-(-5.364×10)

u = 0+53.64

u = 53.64 m/s

6 0
3 years ago
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