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100N divide 2 by 200 it is 100
Answer:
When x = 2.8 cm, 
When x = 5.5 cm, 
when x = 7.3 cm, 
When x = 11.0 cm, 
Explanation:
According to Biot-Savart law,
.......................(1)
R = 11.0 cm = 0.11 m
I = 17.0 A
N = 300 turns

When x₁ = 2.8 cm = 0.028 m

When x₂ = 5.5cm = 0.055 m

When x₃ = 7.3 cm = 0.073 m

When X₄ = 11.0 cm = 0.11 m

Answer:
Explanation:
The melting point of the solid is 80°C
Vapor point of the liquid is 140°C
What happens to particles of X when heated from 70°C to 85°C?
- Firstly, there would be a phase change from solid to liquid.
- Below the melting point, a substance will exist as a solid.
- With increase in thermal energy inputted by heat, as the temperature climbs above the melting point, it changes to the liquid.
- When the solid begins to heat up, the particles of X starts vibrating about their fixed point.
- At they melting point, they break lose and flow to form a liquid.
- The particles will have more kinetic energy.
Answer:
0.167m/s
Explanation:
According to law of conservation of momentum which States that the sum of momentum of bodies before collision is equal to the sum of the bodies after collision. The bodies move with a common velocity after collision.
Given momentum = Maas × velocity.
Momentum of glider A = 1kg×1m/s
Momentum of glider = 1kgm/s
Momentum of glider B = 5kg × 0m/s
The initial velocity of glider B is zero since it is at rest.
Momentum of glider B = 0kgm/s
Momentum of the bodies after collision = (mA+mB)v where;
mA and mB are the masses of the gliders
v is their common velocity after collision.
Momentum = (1+5)v
Momentum after collision = 6v
According to the law of conservation of momentum;
1kgm/s + 0kgm/s = 6v
1 =6v
V =1/6m/s
Their speed after collision will be 0.167m/s