Answer:
x=√139-3, x=-√139-3
Step-by-step explanation:
to complete the square, you first move the constant to the other side of the equation-its already done for you!
now, you find the perfect square trinomial. You divide the b value by 2, then square it: 6/2=3, 3^2=9.
What you do to one side has to be done with the other.
x^2+6x+9=130+9
now you can factor the square:
(x+3)^2=139
squareroot both sides:
x+3=√139
x+3=-√139
now subtract both sides by 3
x=√139-3
x=-√139-3
Answer:
B.
Step-by-step explanation:
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Answer:
Once the equation is in standard form, factor the quadratic expression. 2x2 + 7x + 3 = 0 (2x + 1)(x + 3) = 0. Using the Zero Product Property set ...
2x2 + 7x = -3
2x2 + 7x + 3 = 0
Once the equation is in standard form, factor the quadratic expression.
2x2 + 7x + 3 = 0
(2x + 1)(x + 3) = 0
Using the Zero Product Property set each factor equal to 0 and solve for x.
2x + 1 = 0
2x + 1 - 1 = 0 - 1 x + 3 = 0
2x = -1 x + 3 - 3 = 0 - 3
2x 2 = -1 2 x = -3
x = -1 2
The solutions to the equation are -1 2 and -3.
Answer:
3=b
Step-by-step explanation:

<h3>
Answer: D) 5</h3>
Reason: It's the largest exponent
When a polynomial is written in standard form like this, the term with the largest exponent is written first, then the next largest and so on. So in cases like this, we simply need to look at the left-most term; however, this may not always be the case as your teacher could easily mix up the terms to make sure you're paying attention.
This is considered a quintic polynomial due to the degree of 5.