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posledela
3 years ago
15

Bob is selling floral arrangements. Each arrangement uses 1 vase and 15 tulips. Each vase costs Bob $4.00. Let C be the total co

st of the arrangement and t be the cost of 1 tulip. Write an equation, in slope-intercept form, that represents the total cost of each arrangement to Bob
Mathematics
2 answers:
patriot [66]3 years ago
8 0
C = t(15x) + 4... I think that would be it but I'm not completely sure.
SCORPION-xisa [38]3 years ago
7 0
Y=t(15)+4 Is what I think this word problem would be written in Slope-intercept form. 
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41 to the nearest degree
Elden [556K]
The nearest degree would be 40
4 0
3 years ago
The length of a rectangle is 5 centimeters less than twice it’s width. The perimeter of the rectangle is 80 cm. What are the dim
algol [13]
<h3><u>The length is equal to 25.</u></h3><h3><u>The width is equal to 15.</u></h3>

l = 2w - 5

2l + 2w = 80

We have a value for l, so we can plug it into the second equation to solve for w.

2(2w - 5) + 2w = 80

Distributive property.

4w - 10 + 2w = 80

Combine like terms.

6w - 10 = 80

Add 10 to both sides.

6w = 90

Divide both sides by 6.

w = 15

Now that we have a value for w, we can plug it into the original equation to solve for l.

l = 2(15) - 5

l = 30 - 5

l = 25


3 0
3 years ago
36.00x0.07 show explanation
makkiz [27]

Answer: 2.52

Step-by-step explanation: 36.00x0.07

36.00 is the same as 36

so, 36x0.07=2.52

5 0
2 years ago
Which is a true statement about angles 1 and 2? O the two angles are supplementary
lana66690 [7]
C neither
Thank you hope this helps
5 0
3 years ago
The graph of the function f(x) = (x − 3)(x + 1) is shown.
Nutka1998 [239]
Option A. All the real values of x where x < -1

Procedure
Solve the inequality:
(x -3)(x+1)>0
That happens in two cases.

1) When both factors >0
x-3>0 and x+1>0
x>3 and x >-1

The intersection is x >3

2) When both factors <0
x-3<0 and x+1<0
x<3 and x<-1

the intersection is x<-1.

We have obtained that the function is positive for the intervals  x < -1 and x > 3. But in one of those intervals the function is decresing and in the other is increasing.

You can recognize that the function given is a parabola and, because the coefficient of the quadratic term is positive, the parabola opens upward. Then the function is decreasing in the  first interval and increasing in the second interval.
6 0
3 years ago
Read 2 more answers
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