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Rudiy27
2 years ago
12

10/8c - 4/8 = 6/8 + 5/8c​

Mathematics
1 answer:
siniylev [52]2 years ago
5 0

Answer: c = 2

Step-by-step explanation: Solve for c by simplifying both sides of the equation, then isolating the variable.

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Simplifying expressions with exponents
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When dividing two terms with the same base, subtract the exponent in the denominator from the exponent in the numerator: Power of a Power: To raise a power to a power, multiply theexponents. 
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3 years ago
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What is the area of the polygon? <br> 6 inches 3 inches​
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Area of polygon = 1/2 pa. So it would be 0.5 x 6 x 3. The fire the area is 9
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The density of a certain material is such that it weighs 9 kilograms for every 7 cubic feet of volume. Express this density in p
Vadim26 [7]

Answer:

1.641× 10^-3 pounds/ cubic inch

Step-by-step explanation:

Density= mass / volume

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Volume= 7 cubic feet

Density= 9/7= 1.286 kg/ ft^3

Density= 1.286 kg/ ft^3

To Convert to pounds per inch

1 kg/ ft^3 = 0.00128 pound / cubic inch

1.286 kg/ ft^3 = X pounds/ cubic inch

X=( 1.286 × 0.00128)

= 0.0016407087 pounds/ cubic inch

= 1.641× 10^-3 pounds/ cubic inch

Hence,this density in pounds per inch is 1.641× 10^-3 pounds/ cubic inch

5 0
3 years ago
Differentiation. questions 1 and 2
drek231 [11]
For 11, we start by plugging 1 in, getting 2(1)^2+1-5=-2=y

Plugging 1+m instead, we get 2(1+m)^2+1+m-5=2(1+2m+m^2)+1+m-5
= 2+4m+2m^2+1+m-5= 2m^2+5m-2. We have to find the difference between that and -2, so 2m^2+5m-2 -(-2)=2m^2+5m

Differentiating 12, we use the Power Rule to get -6x^2+14, and plugging x=1 into it, we get -6(1)^2+14=-6+14=18
4 0
4 years ago
6.5 + (−2) + 10.5 I could probably do this but its kind of hard to understand. Explain?
elena-s [515]
Hello! Let's work this problem from left to right to make things a bit easier ;)

6.5+(-2) is the same as 6.5-2, since adding a negative is the same as subtracting a positive. 6.5-2=4.5

Now, we have to add 10.5 to 4.5, which gives us the grand total of 15. I hope this helped! Let me know if you need anything else!
6 0
3 years ago
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