Let x,y be two different numbers
suppose x^2=y^2
then x^2-y^2=0
which yields (x+y)(x-y)=0
so either x=y or x=-y
In any case, x and y must be the same value
also when a vairable is squared like y=x^2
we must note that there are 2 possible solutions
x=(+/-)sqrt(y)
150x^5-60x^4-119x^3+5x-6/5x-1
Answer:
Number A. is True. B. is False. C. is IDK D. is False. E. is true.
Step-by-step explanation:
If you read it you can tell plus I broke it down and solved it on paper.
Answer:
4 trees
Step-by-step explanation:
40/10=4