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Alchen [17]
3 years ago
13

At a high school cafeteria, diners can choose one vegetable from a choice of 2 vegetables, one meat from a choice of 2 meats, on

e serving of bread from among 3 breads, and a dessert from among 3 desserts. How many meal configurations are possible?
A.10
B.36
C.4
D.12
E.18
Mathematics
2 answers:
FrozenT [24]3 years ago
7 0
The  best option is B.
Margarita [4]3 years ago
5 0
2*2*3*3=36, so it is (B)
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Assuming the equation is:

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If we do that, the solution will be:

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solve

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with the same results.

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4 years ago
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