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Alchen [17]
3 years ago
13

At a high school cafeteria, diners can choose one vegetable from a choice of 2 vegetables, one meat from a choice of 2 meats, on

e serving of bread from among 3 breads, and a dessert from among 3 desserts. How many meal configurations are possible?
A.10
B.36
C.4
D.12
E.18
Mathematics
2 answers:
FrozenT [24]3 years ago
7 0
The  best option is B.
Margarita [4]3 years ago
5 0
2*2*3*3=36, so it is (B)
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You must fine 2 number that multiply to equal -27 and add to equal -6

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x - 9 = 0
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You must get x by its self.
When you do so, you'll have the answer as -3 and 9
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a coin operated machine sells plastic rings . it contains 6 yellow rings,11 blue rings,15 green rings,and 3 black rings.sarah pu
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Chau will rent a car for the weekend. He can choose one of two plans. The first plan has an initial fee of $44 and costs an
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2 years ago
Simplify. 14+4(12−34)2 Enter your answer in the box.
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5 0
3 years ago
Read 2 more answers
OperumONS UNTUI a) Find the greatest number that divides 36, 45 and 63 without leaving a remainder. b) c) Find the greatest numb
larisa86 [58]

Answer:

a) The greatest number that divides 36, 45, and 63 without leaving a remainder is 9

b) The greatest number which exactly divides 90, 120, and 150 is 30

c) The greatest capacity of the bucket is 10 liters

d) The greatest number of people to whom the items can be distributed equally is 40 people

ii) 2 kg of wheat flour, 3 kg of corn and 4 kg of rice

e) The greatest number of children to whom the 48 orange, 80 bananas, and 144 apples can be distributed equally is 16

ii) 3 oranges, 5 bananas and 9 apples each

f) 5 mangoes at a time from the basket containing 120 mangoes

7 mangoes at a time from the basket containing 168 mangoes

g) The greatest length of each squared marble is 2 m

Step-by-step explanation:

a) The greatest number that divides 36, 45, and 63 without leaving a remainder = The highest common factor of 36, 45, and 63, which is given as follows;

36 = 9 × 4

45 = 9 × 5

63 = 9 × 7

Therefore, The greatest number that divides 36, 45, and 63 without leaving a remainder  = The highest common factor of 36, 45, and 63 = 9

b) 90 = 30 × 3

120 = 30 × 4

150 = 30 × 5

The greatest number which exactly divides 90, 120, and 150 is 30

c) The factors of the volumes are;

50 l = 10 × 5 l

60 l = 10 × 6 l

70 l = 10 × 7 l

Therefore, the greatest capacity of the bucket = 10 liters

d) The masses of the items are

The factors of 80 = 40 × 2

120 = 40 × 3

160 = 40 × 4

Therefore the items can be distributed equally to 40 people

ii) Each person gets 2 kg of wheat flour, 3 kg of corn and 4 kg of rice

e) 48 = 16 × 3

80 = 16 × 5

144 = 16 × 9

Therefore, the greatest number of children = 16

ii) Each child gets 3 oranges, 5 bananas and 9 apples

f) The factors of 120 = 24 × 5

168 = 24 × 7

Therefore;

The greatest number of mangoes which is to be taken out of the basket with 120 mangoes = 5 mangoes each (24 times)

The greatest number of mangoes which is to be taken out of the basket with 168 mangoes = 7 mangoes each (24 times)

g) The area of the floor = 12 m × 10 m = 120 m²

The factor of 120 m² which is a perfect square is 4 therefore, we have;

The side length of each squared marble, s = √4 = 2

The side length of each squared marble, s = 2 m

7 0
3 years ago
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