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2 years ago

PLEASE HELP ASAP!

Mathematics

1 answer:

Ann [662]2 years ago

3 0

A rhombus is a quadrilateral whose all sides are of equal length, and the opposite are parallel to each other.

<h3>What is a Rhombus?</h3>

A rhombus is a quadrilateral whose all sides are of equal length, and the opposite are parallel to each other.

Given the diagonal MO divides the rhombus LMNO, is two isosceles triangles, therefore, ΔLMO and ΔMNO.

Since the triangles are isosceles triangles two of the sides of the triangle will be of the same length. Therefore,

In ΔLMO

LM = LO

In ΔMNO

MN = ON

since it is the property of the rhombus that the length of its adjacent sides is equal, therefore, the LMNO is a rhombus.

Learn more about Rhombus:

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Using a graphing utility, find the exact solutions of the system. Round to the nearest hundredth and choose a solution to the sy

Margaret [11]

Answer:

Part 1) The exact solutions are

$(\frac{-1+\sqrt{21}} {2},4+\sqrt{21})$ and $(\frac{-1-\sqrt{21}} {2},4-\sqrt{21})$

Part 2) (1.79, 8.58)

Step-by-step explanation:

we have

$y=x^{2} +3x$ ----> equation A

$y=2x+5$ ----> equation B

we know that

When solving the system of equations by graphing, the solution of the system is the intersection points both graphs

Find the exact solutions of the system

equate equation A and equation B

$x^{2} +3x=2x+5\\x^{2} +3x-2x-5=0\\x^{2} +x-5=0$

The formula to solve a quadratic equation of the form

$ax^{2} +bx+c=0$

is equal to

$x=\frac{-b\pm\sqrt{b^{2}-4ac}} {2a}$

in this problem we have

$x^{2} +x-5=0$

$a=1\\b=1\\c=-5$

substitute in the formula

$x=\frac{-1\pm\sqrt{1^{2}-4(1)(-5)}} {2(1)}$

$x=\frac{-1\pm\sqrt{21}} {2}$

The solutions are

$x_1=\frac{-1+\sqrt{21}} {2}$

$x_2=\frac{-1-\sqrt{21}} {2}$

Find the values of y

First solution

For $x_1=\frac{-1+\sqrt{21}} {2}$

$y=2(\frac{-1+\sqrt{21}} {2})+5$

$y=-1+\sqrt{21}+5\\\\y=4+\sqrt{21}$

The first solution is the point $(\frac{-1+\sqrt{21}} {2},4+\sqrt{21})$

Second solution

For $x_2=\frac{-1-\sqrt{21}} {2}$

$y=2(\frac{-1-\sqrt{21}} {2})+5$

$y=-1-\sqrt{21}+5\\\\y=4-\sqrt{21}$

The second solution is the point $(\frac{-1-\sqrt{21}} {2},4-\sqrt{21})$

Round to the nearest hundredth

First solution

$(\frac{-1+\sqrt{21}} {2},4+\sqrt{21})$ -----> $(1.79,8.58)$

$(\frac{-1-\sqrt{21}} {2},4-\sqrt{21})$ -----> $(-2.79,-0.58)$

see the attached figure to better understand the problem

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3 years ago

Write an absolute value for all real numbers at least 3 units from -2

guajiro [1.7K]

{xi,...}|3|≥xsomething like this

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3 years ago

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egoroff_w [7]

Answer: 1 gallon

Step-by-step explanation:

Hi there!

Using the equation (12*18)-(7*3), where 12*18 is the area of the wall, 7*3 is the area of the door not being painted, you are left with 196 square ft. of wall. further dividing 196/200 is 0.98, meaning that Mr. Smith will only need one gallon of paint for his wall.

[(12*18)-(7*3)]/200

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2 years ago

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MaRussiya [10]

Answer:

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