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2 years ago

Use distributive property to remove the parentheses. Simplify your answer as much as possible please.

Mathematics

1 answer:

slavikrds [6]2 years ago

7 0

Answer:

28y^3 -35y^5

Step-by-step explanation:

= 7y^3(4) -7y^3(5y^2)

= 28y^3 -35y^5

_____

The applicable rule of exponents is ...

(y^a)(y^b) = y^(a+b)

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Simplify the expression:<br><br> –3(9 − x) =

steposvetlana [31]

Answer:

Expand $-3(9-x): -27 + 3x$

Step-by-step explanation:

$-3(9-x)$

Apply the distributive law: $a(b-c)=ab-ac$

$a = -3, b=9, c=x$

$=-3*9-(-3)x$

Apply minus - plus rules:

$-(-a)=a$

$= -3*9+3x$

Multiply the numbers: $3 * 9 = 27$

$=-27+3x$

Hope this helps! If so, may I get Brainliest and a Thanks?

Thank you, have a good one! =)

6 0

3 years ago

Find all the zeros of the equation

lapo4ka [179]

Divide both sides by -3, and replace $x^2$ with $y$ . Then

$-3x^4+27x^2+1200=0\iff y^2-9y-400=0$

Factorize the quadratic in $y$ to get

$y^2-9y-400=(y+16)(y-25)=0\implies y=-16,y=25$

which in turn means

$x^2=-16,x^2=25$

But $x^2\ge0$ for all real $x$ , so we can ignore the first solution. This leaves us with

$x^2=25\implies x=\pm\sqrt{25}=\pm5$

If we allow for any complex solution, then we can continue with the solution we ignored:

$x^2=-16\implies x=\pm\sqrt{-16}=\pm i\sqrt{16}=\pm4i$

6 0

4 years ago

HELP PLSSSSSSSSSSSSSS!!!!!!!!!!!!!! I will Give Brainlyest!!!

Ymorist [56]

Answer:

$\frac{21}{8}$

Step-by-step explanation:

$6\frac{1}{4}=6+\frac{1}{4}=\frac{25}{4}\\\\3\frac{5}{8}=3+\frac{5}{8}=\frac{29}{8}\\$

finally

$6\frac{1}{4}-3\frac{5}{8}=\frac{25}{4}-\frac{29}{8}=\frac{21}{8}$

5 0

3 years ago

Read 2 more answers

Darla is playing a computer game to help her learn about science. her scores for the first six games were 9, 12, 10, 8, 14, and

Greeley [361]

Darla would have to score 16 on the next game

7 0

3 years ago

Read 2 more answers

What is sin(4a) & cos(4a) if tan(a)=3

ratelena [41]

Answer:

sin(4a) = -24/25
cos(4a) = 7/25

Step-by-step explanation:

Your calculator can tell you these values:

sin(4a) = sin(4·arctan(3)) = -0.96 = -24/25

cos(4a) = cos(4·arctan(3)) = 0.28 = 7/25

_____

Some useful trig identities are ...

sin(2a) = 2tan(a)/(1 +tan(a)^2)

cos(2a) = (1 -tan(a)^2)/(1 +tan(a)^2)

Filling in the given value for tan(a), we find ...

sin(2a) = 2(3)/(1+3^2) = 6/10 = 3/5

cos(2a) = (1 -3^2)/(1 +3^2) = -8/10 = -4/5

Now, double-angle formulas are useful:

sin(4a) = 2sin(2a)cos(2a) = 2(3/5)(-4/5) = -24/25

cos(4a) = 1 -2sin(2a)^2 = 1 -2(3/5)^2 = 7/25

The desired trig function values are sin(4a) = -24/25; cos(4a) = 7/25.

6 0

3 years ago