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Nastasia [14]
3 years ago
15

Please help me my queston is the photo

Mathematics
2 answers:
Agata [3.3K]3 years ago
7 0

10.54cm2

This is the sense
exis [7]3 years ago
6 0

Answer:

the answer is 10.54 cm2

Step-by-step explanation:

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B.

Step-by-step explanation:

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Square root of 1536 with divison method
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HELP ASAP I NEED IT!!
nevsk [136]

Answer:

The two complex numbers that make the equation true are 1 + i  and 3 + 2i

(1 + i) + (3 + 2i) = 4 + 3i

Step-by-step explanation:

(1 + i) + (3 + 2i)

Combine the real and imaginary parts in numbers 1 + i and 3 + 2i

1 + 3 + (1 + 2)i

Add 1 to 3. Add 1 to 2.

4 + 3i

The two complex numbers that make the equation true are 1 + i  and 3 + 2i

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2 years ago
Please help! All the questions.
Yuri [45]
5) 33-25
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5 0
3 years ago
Suppose that $3000 is placed in an account that pays 16% interest compounded each year. Assume that no withdrawals are made from
Papessa [141]

Answer:

a) $3480

b) $4036.8

Step-by-step explanation:

The compound interest formula is given by:

A(t) = P(1 + \frac{r}{n})^{nt}

Where A(t) is the amount of money after t years, P is the principal(the initial sum of money), r is the interest rate(as a decimal value), n is the number of times that interest is compounded per year and t is the time in years for which the money is invested or borrowed.

Suppose that $3000 is placed in an account that pays 16% interest compounded each year.

This means, respectively, that P = 3000, r = 0.16, n = 1

So

A(t) = P(1 + \frac{r}{n})^{nt}

A(t) = 3000(1 + \frac{0.16}{1})^{t}

A(t) = 3000(1.16)^{t}

(a) Find the amount in the account at the end of 1 year.

This is A(1).

A(t) = 3000(1.16)^{t}

A(1) = 3000(1.16)^{1} = 3480

(b) Find the amount in the account at the end of 2 years.

This is A(2).

A(2) = 3000(1.16)^{2} = 4036.8

4 0
3 years ago
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