Find two numbers whose difference is 12 and whose sum is 40
1 answer:
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Step-by-step explanation:
Step 1: Write our Givens
Move the constant term ,(the term with no variable) to the right side.
Here we have a negative 7, so we add 7 to both sides
Next, we take the linear coeffeicent and divide it by 2 then square it.
Then we add that to both sides
Next, we factor the left,
we got 5 because 5 add to 10 and multiply to 25 as well.
so we get
This is called a perfect square trinomial.
Next, we take the square root of both sides
± menas that we have a positive and negative solution.
Subtract 5 form both side so we get
The greater solution is when sqr root of 32 is positive so the answer to that is