The type and number of solutions is (b) two imaginary solutions.
<h3>How to determine the type and number of solutions?</h3>
The equation is given as:
3x² + 5x + 5 = 0
A quadratic equation can be represented as:
ax^2 + bx + c = 0
Where, the discriminant (d) is
d = b^2 - 4ac
So, we have
d = 5^2 - 4 * 3 * 5
Evaluate
d = -35
The value of d is negative
This means that the equation has only imaginary solutions
Hence, the type and number of solutions is (b) two imaginary solutions.
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There will be a 25 grams left after 3240 years.
The half-life of Radium-226 is 1620 years. If we divide 3240 by 1620 the answer is 2. So that means the amount of Radium-226 will divide in half twice.
100 / 2 = 50 / 2 = 25
<span>Answer 61 73-66= 7 21-13 = 8 ?? -52= 9 20-10 = 10 ??=61</span>
Answer:
1253/250
Step-by-step explanation:
Answer:
RS = 5
Step-by-step explanation:
Since R is between Q and S , then
QS = QR + RS , that is
6x - 3 = 3x - 2 + 2x + 1
6x - 3 = 5x - 1 ( subtract 5x from both sides )
x - 3 = - 1 ( add 3 to both sides )
x = 2
Then
RS = 2x + 1 = 2(2) + 1 = 4 + 1 = 5
