P1=(0,0)=(x1,y1)→x1=0, y1=0
P2=(3,-2)=(x2,y2)→x2=3, y2=-2
Slope: m=(y2-y1)/(x2-x1)
m=(-2-0)/(3-0)
m=(-2)/3
m=-2/3
Point-slope equation:
y-y1=m(x-x1)
y-0=(-2/3)(x-0)
y=-(2/3)x
Answer: The equation of the line is: y=-(2/3)x
Answer:
A
Step-by-step explanation:
hope it helps
The goal of this function is to get a positive value under the square root sign so that the value would not be invalid. Evaluating F(3,1), the value is 1 + <span>sqrt(4-1^2) or equal to 1 + sqrt of 3.</span> In this case, the domain would be x equal to any numbers and the range equal to numbers from -2 ≤ y ≤ 2.
I believe the answer would be 11.99, because 20% times 59.95 is 11.99
Answer:
you multiply the first the square Indian that will give you the essay equals in a square
