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2 years ago

For the following pairs of equations explain why the equations are NOT equivalent.

Mathematics

1 answer:

Serga [27]2 years ago

7 0

If you were to make both x's equivalent, you'd have to multiply the first equation by 2 to get rid of the coefficient, 1/2. However, you'd have to multiply 2 onto -8 as well, therefore the equation would turn into x - 16 = 18. That is not equivalent to x - 8 = 18.

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Find the output of the function machine<br>9 √<br><br>

Afina-wow [57]

Answer:

Step-by-step explanation:

Assuming a typo in your question. Sqrt(9) = 3

5 0

3 years ago

Subtract fractions with different denominators

Tems11 [23]

Answer:

$\frac{10}{15}-\frac{2}{5}=\frac{4}{15}$

Step-by-step explanation:

We know that

A fraction consists of two integers—one on the top, and one on the bottom.
The top one is numerator, the bottom one is denominator, and
These two numbers are separated by a line.

Let us consider two different fractions with different denominators

$\frac{10}{15}$

$\frac{2}{5}$

Lets subtract the two fractions

$\frac{10}{15}-\frac{2}{5}\:\:\:\:$

$\mathrm{Cancel\:}\frac{10}{15}:\quad \frac{2}{3}$

$=\frac{2}{3}-\frac{2}{5}$

$\mathrm{Least\:Common\:Multiplier\:of\:}3,\:5:\quad 15$

$\mathrm{Adjust\:Fractions\:based\:on\:the\:LCM}$

$\mathrm{For}\:\frac{2}{3}:\:\mathrm{multiply\:the\:denominator\:and\:numerator\:by\:}\:5$

$\frac{2}{3}=\frac{2\cdot \:5}{3\cdot \:5}=\frac{10}{15}$

$\mathrm{For}\:\frac{2}{5}:\:\mathrm{multiply\:the\:denominator\:and\:numerator\:by\:}\:3$

$\frac{2}{5}=\frac{2\cdot \:3}{5\cdot \:3}=\frac{6}{15}$

$=\frac{10}{15}-\frac{6}{15}$

$\mathrm{Since\:the\:denominators\:are\:equal,\:combine\:the\:fractions}:\quad \frac{a}{c}\pm \frac{b}{c}=\frac{a\pm \:b}{c}$

$=\frac{10-6}{15}$

$\mathrm{Subtract\:the\:numbers:}\:10-6=4$

$=\frac{4}{15}$

Therefore,

$\frac{10}{15}-\frac{2}{5}=\frac{4}{15}$

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2 years ago

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Scrat [10]

Answer:

slope of line is 3/5

Step-by-step explanation:

slope is the ratio of the change in the y-values over the change in the x-values

in this problem, if you go from pt A to pt B, you rise by 3 and go to the right by 5, thus slope of 3/5

if you go from pt B to pt C, you rise by 6 and go to the right by 10

however, 6/10 can be reduced to 3/5

if you start at point (0,2) and rise by 3 and run to the right by 5 you are at point (5,5)

change in y-values is 5-2 or 3

change in x-values is 5-0 or 5

(5-2)/(5-0) = 3/5

3 0

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a_sh-v [17]

10+5=5+10
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Commutative Property of Addition is used.

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