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Phantasy [73]
4 years ago
10

Freemont Run Club surveyed a random sample of 30 of their members about their running habits. Of the members surveyed, 9 said th

at they run more than 5 days a week. There are 84 Freemont Run Club members. Based on the data, what is the most reasonable estimate for the number of Freemont Run Club members who run more than 5 days a week?
Mathematics
2 answers:
NISA [10]4 years ago
8 0
25 members
...................

Hope this helps
Sphinxa [80]4 years ago
7 0
9/30 = 0.3

0.3 * 84 = 25.2

Round 25.2 : 

25.2 rounded to the nearest whole number = 25

The answer is 25.

Hope this helped☺☺
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For a certain horse race comma the odds in favor of a certain horse finishing in second placehorse race, the odds in favor of a
NikAS [45]

Answer:

0.33

Step-by-step explanation:

Let A denote an event. The odds of the horse finishing second is 33 to 67.

From the information, the total outcomes of event A is:

Total \ Outcomes, A=Favorable +Unfavorable\\\\=33+67\\\\=100

Hence, there are 100 total outcomes. The probability of the horse finishing second is calculated as:

p=\frac{n(A_f)}{n(A_u)}\\\\\\=p=\frac{33}{100}\\\\=0.33

Hence, the probability of finishing second is 0.33

7 0
3 years ago
Chemicals in butter-flavoring: Workers in a microwave popcorn production plant in Missouri breathe chemicals that are part of th
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6 0
3 years ago
Read 2 more answers
Pleas help will mark best answer!! <3
natali 33 [55]
You have 4 walls, 2 with length 12 feet, 2 with length 15 feet and each of them has a height of 12 feet
so you sum all the lengths and then multiply it by the height to get the total area

total length=2*(12+15)
=2*(27)
=54
total area=total length*ceiling height
=54*12
=648 feet^2 to cover all walls with wallpaper
8 0
3 years ago
The scale on a trail map is 0.5 cm : 1 km. The straight distance between 2 huts on the trail is 16.9 cm. What is the actual dist
sesenic [268]

We have been given that the scale on a trail map is 0.5 cm : 1 km. The straight distance between 2 huts on the trail is 16.9 cm. We are asked to find the actual distance between 2 huts.

We will use proportions to solve our given problem.

\frac{\text{Actual length}}{\text{Scale length}}=\frac{\text{1 km}}{\text{0.5 cm}}

\frac{\text{Actual length}}{\text{16.9 cm}}=\frac{\text{1 km}}{\text{0.5 cm}}

\frac{\text{Actual length}}{\text{16.9 cm}}\times \text{16.9 cm}=\frac{\text{1 km}}{\text{0.5 cm}}\times \text{16.9 cm}

\text{Actual length}=\frac{\text{1 km}}{\text{0.5}}\times \text{16.9}

\text{Actual length}=33.8\text{ km}

Therefore, the actual distance between both huts is 33.8 km.

6 0
3 years ago
A cone has radius 9 and a height 12. A frustum of this cone has height 4.
Anettt [7]

Answer:

Part A)

The lower base has a radius of 9 units, and the upper base has a radius of 6 units.

Part B)

5 units.

Part C)

75π or about 235.62 square units.

Step-by-step explanation:

Please refer to the figure below.

The cone has a radius of 9 units and a total height of 12 units.

A frustum of the cone has a height of 4 units.

Part A)

The lower radius of the frustum will simply be 9 units.

For the upper radius, we will use the properties of similar triangles. We will compare the smaller upper triangle to the overall larger triangle. This yields:

\displaystyle \frac{12}{8}=\frac{9}{x}

Solve for <em>x.</em> Simplify:

\displaystyle \frac{3}{2}=\frac{9}{x}

Cross-multiply:

18=3x\Rightarrow x=6

The upper base has a radius of 6 units.

Part B)

We can first find the total slant height of the entire cone. By using the Pythagorean Theorem, this yields that the total slant height is:

SH^2=12^2+9^2

Simplify:

SH^2=225\Rightarrow SH=15\text{ units}

Now, find the slant height of the upper cone:

(SH_\text{cone})^2=8^2+6^2=100

So:

SH_\text{cone}=10

Then the slant height of the frustum will be the cone subtracted from the total. Thus:

SH_{\text{frustum}}=15-10=5\text{ units}

Part C)

We can first find the lateral area of the entire cone. The lateral area is given by:

LA=\pi r\ell

The lateral area of the entire cone will be:

LA=\pi (9)(15)=135\pi

The lateral area of the upper cone will be:

LA_\text{cone}=\pi(6)(10)=60\pi

Then the lateral area of the frustum is:

LA_\text{frustum}=135\pi-60\pi =75\pi\text{ units}^2\approx235.62\text{ units}^2

5 0
3 years ago
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