Each probability can be written as y/4, since there are four different possible outcomes. Also, it's worth noting that if you add the three up they will equal 4/4 or 1.
Put super simply, of HH, HT, TH, TT how many have zero Hs, how many have 1 H and how many have 2 Hs? These are the answers to a, b and x respectively.
Answer: 266 boys Because there are 304 girls we do 304/8=38 now we do 38 multiplied by 7 (as that is the ratio for the number of boys) 38*7=266 boys Hope this helped
