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3 years ago

A coin is tossed two times. The set of outcomes is

Mathematics

2 answers:

Jlenok [28]3 years ago

7 0

Answer:

Step-by-step explanation:

Each probability can be written as y/4, since there are four different possible outcomes. Also, it's worth noting that if you add the three up they will equal 4/4 or 1.

Put super simply, of HH, HT, TH, TT how many have zero Hs, how many have 1 H and how many have 2 Hs? These are the answers to a, b and x respectively.

stira [4]3 years ago

6 0

Answer:

A. 0.25

B. 0.5

C. 0.25

Step-by-step explanation:

NONE

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Simplify: 18 + 8 + 2 (-5) -4 a. -10 b. -18 C. -81 d. -73

Vlada [557]

That would be d -73

7 0

3 years ago

Read 2 more answers

45% to a decimal ples help out

yan [13]

Answer:

45% = 0.45

Step-by-step explanation:

45%

= $\frac{45}{100}$

= 0.45

7 0

3 years ago

Read 2 more answers

A box of Georgia peaches has 3 bad and 12 good peaches. (a) If you make a peach cobbler of 12 peaches randomly selected from the

Eddi Din [679]

Answer:

a) 0.21% probability that there are no bad peaches in the peach cobbler.

b) 99.79% probability of having at least 1 bad peach in the peach cobbler

c) 7.91% probability of having exactly 2 bad peaches in the peach cobbler.

Step-by-step explanation:

A probability is the number of desired outcomes divided by the number of total outcomes.

The order in which the peaches are chosen is not important. So the combinations formula is used to solve this question.

Combinations formula:

$C_{n,x}$ is the number of different combinations of x objects from a set of n elements, given by the following formula.

$C_{n,x} = \frac{n!}{x!(n-x)!}$

(a) If you make a peach cobbler of 12 peaches randomly selected from the box, what is the probability that there are no bad peaches in the peach cobbler?

Desired outcomes:

12 good peaches, from a set of 12. So

$D = C_{12,12} = \frac{12!}{12!(12 - 12)!} = 1$

Total outcomes:

12 peaches, from a set of 15. So

$T = C_{15,12} = \frac{15!}{12!(15 - 12)!} = 455$

Probability:

$p = \frac{D}{T} = \frac{1}{455} = 0.0021$

0.21% probability that there are no bad peaches in the peach cobbler.

(b) What is the probability of having at least 1 bad peach in the peach cobbler?

Either there are no bad peaches, or these is at least 1. The sum of the probabilities of these events is 100%. So

p + 0.21 = 100

p = 99.79

99.79% probability of having at least 1 bad peach in the peach cobbler

(c) What is the probability of having exactly 2 bad peaches in the peach cob- bler?

Desired outcomes:

2 bad peaches, from a set of 3.

One good peach, from a set of 12.

$D = C_{3,2}*C_{12,1} = \frac{3!}{2!(3-2)!}*\frac{12!}{1!(12 - 1)!} = 36$

Total outcomes:

12 peaches, from a set of 15. So

$T = C_{15,12} = \frac{15!}{12!(15 - 12)!} = 455$

Probability:

$p = \frac{D}{T} = \frac{36}{455} = 0.0791$

7.91% probability of having exactly 2 bad peaches in the peach cobbler.

3 0

3 years ago

College freshmen took a psychology exam. If the mean is 80, the SD is 10, and the scores have normal distribution, what percent

gayaneshka [121]

Answer:

(a) 2%

Step-by-step explanation:

A score of 60 is 2 standard deviations below the mean (80 -2·10 = 60). The empirical rule tells you that 95% of the distribution is within 2 standard deviations of the mean. The remaining 5% is split evenly between those that are more than 2 SD above the mean and those that are more than 2 SD below the mean.

That tells you the percentage who failed is about 2.5%. The best answer choice is 2%.

_____

Additional comment

The empirical rule is a little bit sloppy, but it gets you in the ballpark. The actual percentage is closer to 2.275%.

6 0

3 years ago

If f(x) = x2 – 1 and g(x) = 2x – 3, what is the domain

Ainat [17]

Begin by finding the lowest point the quadratic equation can be, the vertex;

x²-1= is just a translation down of the graph x²

vertex; (0, -1) and since the graph of x² would extend to infinity beyond that point, we can say {x| x≥0} for domain and {y| y≥-1}.

For the linear equation, it is possible to have all x and y values, therefore range and domain belong to all real numbers.

Hope I helped :)

5 0

3 years ago