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Fynjy0 [20]
3 years ago
6

1.Find the value of x when y=2

Mathematics
1 answer:
inna [77]3 years ago
8 0

Answer:

lol its 8

Step-by-step explanation:

0kkkkkkkkkkkkk

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For the equation y= x + 5, find the value of y when
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Answer:

a) 3 b) 5 c) 7 d) 9

Step-by-step explanation:

For this, you want to replace x in the equation y=x+5 with each of the values listed.

For the first one, -2, the equation becomes y=-2+5, which is solved to y=3.

For the second one, 0, the equation becomes y=0+5, which is solved to y=5.

For the third one, 2, the equation becomes y=2+5, which is solved to y=7.

For the last one, 4, the equation becomes y=4+5, which is solved to y=9.

**This content involves solving algebraic equations with a known variable, which you may wish to revise. I'm always happy to help!

5 0
3 years ago
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Answer:

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3 years ago
What is the following product? (2 square root 7+3 square root 6)(5 square root 2+4 square root 3)
Xelga [282]

(2\sqrt7+3\sqrt6)(5\sqrt2+4\sqrt3)\qquad\text{use distributive property}\\\\=(2\sqrt7)(5\sqrt2)+(2\sqrt7)(4\sqrt3)+(3\sqrt6)(5\sqrt2)+(3\sqrt6)(4\sqrt3)\\\\=10\sqrt{14}+8\sqrt{21}+15\sqrt{12}+12\sqrt{18}\\\\=10\sqrt{14}+8\sqrt{21}+15\sqrt{4\cdot3}+12\sqrt{9\cdot2}\\\\=10\sqrt{14}+8\sqrt{21}+15\sqrt4\cdot\sqrt3+12\sqrt9\cdot\sqrt2\\\\=10\sqrt{14}+8\sqrt{21}+(15)(2)\sqrt3+(12)(3)\sqrt2\\\\=\boxed{10\sqrt{14}+8\sqrt{21}+30\sqrt3+36\sqrt2}

5 0
3 years ago
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The answer is 22 1/2-18 3/7. first we need to get a common denominator for the fractions. I will do 14. Now we have 22 7/14-18 6/14=4 1/14 ez

Step-by-step explanation:

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