2 years ago

H^-2g for h=3 and g=27

Mathematics

1 answer:

Alexeev081 [22]2 years ago

3 0

Plug h = 3 and g = 27 into the expression:

$h^{-2}g= \dfrac{g}{h^2} = \dfrac{27}{3^2} = \dfrac{27}{9} = 3$

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For the answer to the question above, I'll provide my solutions to my answers for the problem below.

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