I hope this helps you
a=C/8.pi.b
Answer: the answers are below
Step-by-step explanation:
1 meal = 2/3 of a can of wet dog food, 1/8 of a bag of dry dog food, and 3/5 a patty of special meat
Food for 1 day: 2 meals = 2(2/3) = 4/3 of a can of wet dog food, 2(1/8) = 1/4 of a bag of dry dog food, and 2(3/5) = 6/5 a patty of special meat
The trainer goes to the store and buys 24 cans of wet food, 4 bags of dry food and 3 packages of meat (3*6 = 18 patties)
He has:
there is wet food for: 24/(4/3) = 24*3/4 = 18 days
there is dry food for: 4/(1/4) = 4*4 = 16 days
there is special meat food for: 18/(6/5) = 18*5/6 = 15 days
since the minimum for 15, 16 and 18 is 15 the dog will have food for 15 days and first he will run out of special meat.
Answer:
Confidence limit = [52.8%, 75.2%]
Step-by-step explanation:



±

where the value
will be taken from the z-table for 95% confidence interval
1-0.95= 0.05/2= 0.025
0.95+0.025= 0.0975
From the z-table the value of
corresponding to 0.0975 is 1.96
±

±

± 
% ±
%
so the confidence interval is
%
%
![[52.8, 75.2]](https://tex.z-dn.net/?f=%5B52.8%2C%2075.2%5D)
Answer:
A. z = 2292.8 is your answer
Step-by-step explanation:
Isolate the variable (z). Note the equal sign, what you do to one side, you do to the other. Add 1092.8 to both sides
z - 1092.8 (+1092.8) = 1200 (+1092.8)
z = 1200 + 1092.8
z = 2292.8
A. z = 2292.8 is your answer
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Is that everything for the problem??
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