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2 years ago

10

Matt spent 1/3 of the money in his pocket on a movie ticket. he spent 1/4 of the money on a snack. what fraction of his money is

left?

1 answer:

Alenkasestr [34]2 years ago

5 0

What is left is 5/12 of his money

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Solve each system by substitution

Studentka2010 [4]

Answer:

look, equation ii and vi are contradicting each other....

Step-by-step explanation:

after eliminating those equation you can find the value of x and y.

y=-6

x=3

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2 years ago

–8(x – 4) - (12x – 8)

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Answer:

-20x+128

Step-by-step explanation:

–8(x – 4) - (12x – 8)

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2 years ago

Triangle ABC has vertices at A(-3, 5), B(0, 0), and C(6, 5). It is transformed so that Triangle A'B'C' has coordinates A'(1, 11)

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Jacob is incorrect. The transformation was no a reflection, but a translation. The transation was (x+11,y+6)(11 units rigth and 6 units up). (Explain what the points would have been if it was a reflection across the x-axis)

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2 years ago

Bubba's gym charges a $100 membership fee and $10 per visit.

AlekseyPX

Answer:

C=100+10x

Step-by-step explanation:

its 10$ per visit and x represents the number of visits. and you get a 1 time membership fee of 100 so its 100+10x=C c stand for cost.

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2 years ago

In the past decades there have been intensive antismoking campaigns sponsored by both federal and private agencies. In one study

astra-53 [7]

Answer:

C. z = 2.05

Step-by-step explanation:

We have to calculate the test statistic for a test for the diference between proportions.

The sample 1 (year 1995), of size n1=4276 has a proportion of p1=0.384.

$p_1=X_1/n_1=1642/4276=0.384$

The sample 2 (year 2010), of size n2=3908 has a proportion of p2=0.3621.

$p_2=X_2/n_2=1415/3908=0.3621$

The difference between proportions is (p1-p2)=0.0219.

$p_d=p_1-p_2=0.384-0.3621=0.0219$

The pooled proportion, needed to calculate the standard error, is:

$p=\dfrac{X_1+X_2}{n_1+n_2}=\dfrac{1642+1415}{4276+3908}=\dfrac{3057}{8184}=0.3735$

The estimated standard error of the difference between means is computed using the formula:

$s_{p1-p2}=\sqrt{\dfrac{p(1-p)}{n_1}+\dfrac{p(1-p)}{n_2}}=\sqrt{\dfrac{0.3735*0.6265}{4276}+\dfrac{0.3735*0.6265}{3908}}\\\\\\s_{p1-p2}=\sqrt{0.00005+0.00006}=\sqrt{0.00011}=0.0107$

Then, we can calculate the z-statistic as:

$z=\dfrac{p_d-(\pi_1-\pi_2)}{s_{p1-p2}}=\dfrac{0.0219-0}{0.0107}=\dfrac{0.0219}{0.0107}=2.05$

z=2.05

4 0

2 years ago