Answer:
<u>The correct answer is r = ∛GM*T²/4π²</u>
Step-by-step explanation:
Let's rewrite the formula to find the period of orbit of a satellite around a planet, to solve for r, this way:
T^2=(4pi^2/GM)r^3
T² = (4π²/GM) * r³
r³ = T²/ (4π²/GM)
r³ = T² * GM/4π²
r³ = GMT²/4π²
∛r³ = ∛GM*T²/4π²
r = ∛GM*T²/4π²
<u>The correct answer is r = ∛GM*T²/4π²</u>
Answer:
672
Step-by-step explanation:
anything lower then 5 or in this case 50 would round down so 649 rounds to 600 anything higher would round up 672 to 709 763 to 800 and 751 to 800
Given a quadratic equation

1. the first thing we do when we want to compete the square, is write the coefficient of x as 2 times a number.
In our case the coefficient of x is 10, so we write 10 as 2*5
2. then we write +

and -

to the expression:



Answer:
7.003 has the least value of all the choices given
so, x =

and y =

Hence, the answer is the first one.