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3 years ago

If the midpoint of (4, 3) and point A has coordinates (-2, 6), what are the coordinates of point B?

1 answer:

5 0

(xA+xB)/2, (yA+yB)/2 = (4,3)
(xA+xB)/2 = 4
(-2+xB) = 8 --> xB = 8+2 --> xB = 10
(yA+yB)/2 = 3
(6+yB) = 6 --> yB = 6-6 --> yB = 0

B = (10,0)

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Answer:

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STALIN [3.7K]

<h3><u>Solution</u>:-</h3>

The equation of any straight line can be written as in slope intercept form as -

$\green{ \underline { \boxed{ \sf{y=mx+c}}}}$

where,

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<em><u>Given equation:- </u></em>

$\begin{gathered}\\\implies\quad \sf 5x+y = 10 \\\end{gathered}$

<u>Arranging it in slope intercept form by transposing 5x to RHS </u>

$\begin{gathered}\\\implies\quad \sf y = 10 -5x \\\end{gathered}$

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2 years ago

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Soloha48 [4]

(x-4)^2-11

How?

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Verified

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2 years ago

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lesya [120]

Answer:

Step-by-step explanation:

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