If the midpoint of (4, 3) and point A has coordinates (-2, 6), what are the coordinates of point B?

1 answer:

5 0

(xA+xB)/2, (yA+yB)/2 = (4,3)
(xA+xB)/2 = 4
(-2+xB) = 8 --> xB = 8+2 --> xB = 10
(yA+yB)/2 = 3
(6+yB) = 6 --> yB = 6-6 --> yB = 0

B = (10,0)

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