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olga nikolaevna [1]
4 years ago
7

what are two equivalent expressions to the following radical expression: (√10 to the 4th power x √12 to the 4th power) to the 8t

h power.
Mathematics
1 answer:
brilliants [131]4 years ago
3 0

Answer:

(14400x^4)^8

Step-by-step explanation:

sqrt10 to the 4th is 10^2 or 100, and xsqrt12 to the 4th is 144x^4. Multiply these to get (14400x^4), and take the 8th to get (14400x^4)^8.

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What is 10 x 45 I really need help answering this or my mommy is gonna take my ice cream
sweet [91]

Answer:

450

Step-by-step explanation:

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3 years ago
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Please answer fast need it now like now now!!!!!<br> 10+x&lt;5
katrin [286]
Subtract 10 from both sides
10 + x < 5
10 - 10 + x < 5 - 10
x < -5
So the answer is x < -5, or x is less than -5. Any number less than -5 would be the solution. Hope this helps!
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4 years ago
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The quadratic equation 8x²+12x-14 has two real roots. What is the sum of the squares of these roots?
mars1129 [50]

Answer:

The real roots are

x=\frac{(-3+\sqrt{37})}{4} and x=\frac{(-3-\sqrt{37})}{4}

The sum of the squares of these roots is \frac{-3}{2}

Step-by-step explanation:

The given quadratic equation is 8x^2+12x-14 has two real roots.

To find the roots .

8x^2+12x-14=0

Dividing the above equation by 2

\frac{1}{2}(8x^2+12x-14)=\frac{0}{2}

4x^2+6x-7=0

For quadratic equation ax^2+bx+c=0 the solution is x=\frac{-b\pm\sqrt{b^2-4ac}}{2a}

Where a and b are coefficents of x^2 and x respectively, c is a constant.

For given quadratic equation

a=4, b=6, c=-7

x=\frac{-6\pm\sqrt{6^2-4(4)(-7)}}{2(4)}

=\frac{-6\pm\sqrt{36+112}}{8}

=\frac{-6\pm\sqrt{148}}{8}

=\frac{-6\pm\sqrt{37\times 4}}{8}

=\frac{-6\pm\sqrt{37}\times\sqrt{4}}{8}

=\frac{-6\pm\sqrt{37}\times 2}{8}

=2\frac{(-3\pm\sqrt{37})}{8}

=\frac{-3\pm\sqrt{37}}{4}

x=\frac{(-3\pm\sqrt{37})}{4}

The real roots are

x=\frac{(-3+\sqrt{37})}{4} and x=\frac{(-3-\sqrt{37})}{4}

Now to find the sum of the squares of these roots

\left[\frac{-3+\sqrt{37}}{4}+\frac{(-3-\sqrt{37})}{4}\right]^2=\frac{-3+\sqrt{37}-3-\sqrt{37}}{4}

=\frac{-6}{4}

=\frac{-3}{2}

\left[\frac{-3+\sqrt{37}}{4}+\frac{(-3-\sqrt{37})}{4}\right]^2=\frac{-3}{2}

Therefore the sum of the squares of these roots is \frac{-3}{2}

3 0
3 years ago
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Travka [436]
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7 0
4 years ago
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Question: 3 of 20
zysi [14]

Answer:

Sean earns $7.5 in each hour.

Step-by-step explanation:

Given:

Money earned by Sean = $300

Number of hours worked in a day = 8 hrs

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We need to find Money earned in each hour.

First we will find Total hours work in a week.

Total hours work in a week is equal to Number of hours worked in a day multiplied by number of days work in a week.

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Now we will find money earned for each hour.

Money earned each hour will be calculated by Dividing Total Money earned in a week by Total number of hours worked in a week.

Framing in equation form we get;

Money earned each hour = \frac{300}{40} = \$7.5

Hence Sean earns $7.5 in each hour.

8 0
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