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3 years ago

Help me please I am a idiot who doesn’t get math

Mathematics

1 answer:

lukranit [14]3 years ago

7 0

To calculate the cuboid's volume, use height×width×length which is 11×11×16

For the cylinder's volume, use πr²h. in this case, it is 3.14×4²×9

Add up the two answers you get and that's the solution

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What is written as a decimal? 11/25 help

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The correct answer is 0.44

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Choose the equation that represents the line that passes through the point (−1, 6) and has a slope of −3.

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A) y= -3x +3 and the slope is -3

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Solve - 1.2x + 2.5 = 0.8x + 6.5

lesantik [10]

Answer: x is -2

Steps:

- 1.2x + 2.5 = 0.8x + 6.5

- 1.2x - 0.8x = 6.5 - 2.5

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2 years ago

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A supplementary angle is split into 2 angles. One angle is 2x + 20°. The other angle is 40°. Solve for x and find the measuremen

IrinaVladis [17]

Answer:

x=60 and the missing angle is 140

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40 × 2x + 20= 180

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8 0

3 years ago

A scientist claims that 7% 7 % of viruses are airborne. If the scientist is accurate, what is the probability that the proportio

Reptile [31]

Answer:

The probability is $P(|p-\^{p}| > 0.03) = 0.0040$

Step-by-step explanation:

From the question we are told that

The population proportion is $p = 0.07$

The mean of the sampling distribution is $\mu_p = 0.07$

The sample size is n = 600

Generally the standard deviation is mathematically represented as

$\sigma_p = \sqrt{\frac{p (1 -p)}{n} }$

=> $\sigma_p = \sqrt{\frac{0.07(1 -0.07)}{600} }$

=> $\sigma_p = 0.010416$

Generally the probability that the proportion of airborne viruses in a sample of 600 viruses would differ from the population proportion by greater than 3% is mathematically represented as

$P(|p-\^{p}| > 0.03) = 1 - P(|p -\^{p}| \le 0.03)$

=> $P(|p-\^{p}| > 0.03) = 1 - P(-0.03 \le p -\^{p} \le 0.03 )$

Now add p to both side of the inequality

=> $P(|p-\^{p}| > 0.03) = 1 - P( 0.07-0.03 \le \^{p} \le 0.03+ 0.07 )$

=> $P(|p-\^{p}| > 0.03) = 1 - P(0.04 \le \^{p} \le 0.10 )$

Now converting the probabilities to their respective standardized score

=> $P(|p-\^{p}| > 0.03) = 1 - P(\frac{0.04 - 0.07}{0.010416} \le Z \le \frac{0.10 -0.07}{0.010416} )$

=> $P(|p-\^{p}| > 0.03) = 1 - P(-2.88 \le Z \le 2.88 )$

=> $P(|p-\^{p}| > 0.03) = 1 - [P(Z \le 2.88) - P(Z \le -2.88)]$

From the z-table

$P(Z \le 2.88) = 0.9980$

and

$P(Z \le -2.88) = 0.0020$

$P(|p-\^{p}| > 0.03) = 1 - [0.9980 - 0.0020]$

=> $P(|p-\^{p}| > 0.03) = 0.0040$

7 0

3 years ago