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3 years ago

What is the product of the following expression? 2x(x^2+x-5)

1 answer:

7 0

The first step to solving this expression is to multiply each term in the parenthesis by 2x
2x × x² + 2x × x - 2x × 5
now you need to calculate the first product
2x³ + 2x × x - 2x × 5
now youll calculate the second product of the expression
2x³ + 2x² - 2x × 5
lastly,, calculate the final product in the expression
2x³ + 2x² - 10x
since you cant simplify this expression any further,, the answer to your question is 2x³ + 2x² - 10x
let me know if you have any further questions
:)

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Write an equation in point-slope form of the line that passes through the point (9, 0) and has a slope of m=−3

Softa [21]

Answer:

y=-3(x-9)

Step-by-step explanation:

Point slope form is y-y1=m(x-x1)

x1=9

y1=0

m=-3

plug it all in!

y-0=-3(x-9)

y=-3(x-9)

Hope this helps!

7 0

3 years ago

Plz help me out with this

nadya68 [22]

Given,

HK is the perpendicular bisector of GJ. So, GK = KJ.
GK = 2x + 10
KJ = 3x - 15

_______________

Find KJ .

_______________

First find the value of x

$\sf \: GK \: = KJ \\\sf 2x + 10 = 3x - 15 \\\sf 2x - 3x = - 15 - 10 \\ \sf - x = - 25 \\ \sf \: - > \boxed{\bf \: x = 25}$

Now, find the value of KJ.

$\sf3x - 15 \\ \sf= 3(25) - 15 \\ \sf=7 5 - 15 \\ = \boxed{\bf \: 60}$

-> The value of KJ is 60.

_______________

Hope it helps.

RainbowSalt2222

6 0

3 years ago

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Which of the following capital letters is a reflection image of itself across a horizontal line?

anygoal [31]

Answer:

H is the reflection of itself in the horizontal line

8 0

3 years ago

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X²+7x+10=0 a=1, b=7, c=10 b²-4ac=(7)²-4(1) (10) =49-4(10) =49-40 =9

Sloan [31]

Answer:

X=5

X=2

Step-by-step explanation:

8 0

3 years ago

Allushta [10]

Thanks for the helpful answers

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3 years ago

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