Answer:
a1 = 34, d = 6.
Step-by-step explanation:
a1 = the first term = 34.
To find d subtract: 2nd term - first term , third term - second term and so on.
d = 40 - 34 = 6.
Also 46-40 = 6
WE get the same value 6 for the other given terms.
6 is added to each term to get the next term
To solve this problem you might have to use this formula y=a(1+r)^t A=amount of money you already have 1= a set number R= rate T= time YOUR GIVENS ARE: A=4000 R= 3.5% (0.035) decimals T= 3 years NOW lets plug IN everything in the FORMULA y=4000(1+.035)^3= $4434.87. NOW lets subtract 4000-4434=434. She earned $434 of simple interest.
Answer: Hello mate!
each school graduate has a 68% to find a job in their chosen field within a year after graduation.
And we want to know the probability for a randomly chosen group of 11 graduates to all get a job in their area within a year of graduating.
(you used the numbers 6868% and 1111, I am assuming that you write this wrong and repeated the numbers)
Ok! so each of the 11 students has the same probability of 0.68 to find the job. Then the joint probability for the 11 events ( where the events is that each one finds a job) is the product of the probability for each one.
P = (0.68)^11 = 0.01437
and if we round it to the nearest thousandth we get:
p = 0.014
2005= 18,000
2010= 45,000
1) make 2005 year "0", and 2010 year "5"
2)in order to solve this problem and figure out the rate of change, we must use the equation for exponential functions y=ab^x
3) a= the y- value of y intercept ( what does y equal when x is zero) in this case a population number so, a= 18,000; b= the unknown rate of change; x= time and since we're finding b we can plug in 5 for the time in years; y= the value of y in terms of the x-value, so when x is 5, y is 45,000
4) you end up with something like this
45,000= 18,000b^5
5) in order to proceed to solve you must get b alone
6) divide both sides by 18,000
7) so you no have 2.5= b^5
8) take the fifth root of both sides
9) now you have your answer b=<span>1.20112443398</span>
